Pure acid is to be added to a 10% acid solution to obtain 90L of 81% solution. What amounts of each should be used?

Mathematics

1 answer:

Vlada [557]2 years ago

7 0

Answer:

Step-by-step explanation:

let X be the quantity of 100% acid

let Y be the quantity of 10% acid

X + Y = 90

Y = 90 - X

X(100) + Y(10) = 90(81)

X(100) + (90 - X)(10) = 90(81)

100X + 900 - 10X = 7290

90X = 6390

X = 71 L

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