DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
x=50 y=10
Step-by-step explanation:
Hey!
Your answer is solved below/above idk wherever just see in the picture.
Step-by-step explanation:
the union of two sets is a new sets that contains all of the elements that are in at least one or two sets and written as (A U B)
while intersection of two sets is a new set that contains all of the elements in both sets and written as (A n B)
Answer:
a. connect the point (0 , 3) with A
b. connect the origin (0 , 0) with B
c. For A: y = 0.5x +3
For B: y = 0.5x
Step-by-step explanation:
y = ax + b is the general rule for any straight line
a being the slope and b being the y intercept, a is given to be 0.5
y = 0.5x + b, substitute the coordinates of point A
4 = 0.5 *2 +b hence b = 4 - 0.5 *2 = 4 - 1 = 3
so y = 0.5 x + 3 is the equation of the line passing through A
since the second line that passes through B is parallel to the first, hence it has the same slope of 0.5
same procedure, substitute coordinates of B
2 = 0.5 * 4 + b hence b = 2 - 0.5 *4 = 2 - 2= 0
so y = 0.5 x is the equation of the line passing through B
