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sladkih [1.3K]
3 years ago
6

A sphere has a volume of 36pi in^3 . Find the volume radius of the sphere.

Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

3

Step-by-step explanation:

sergejj [24]3 years ago
6 0

Hi

the volume formula is

V=4 /3 * πr3

<h3>So 113.09in= 4/3 * pi * r cubed</h3><h3>Switch the subject of the formula=</h3><h3>r=(3 V /4π)⅓</h3><h3>So r= Estimating to 3</h3><h3>r= 3</h3><h3>Mark brainliest? </h3><h3> </h3>
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Answer:

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a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.
Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is a_{n} = a^{n-1} \times r

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as a_{1}.

⇒ a_{1} = 612

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

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A geometric series is of the form  a,ar,ar2,ar3,ar4,ar5........

Here, first term a_{1} = a and other terms are obtained by multiplying by r.

  • Observe that each term is r times the previous term.
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The recursive rule is of the form a_{n} = a^{n-1} \times r

This is called recursive formula for geometric sequence.

We know that r = 1.08 and a_{1} = 612.

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⇒ a_{2} = a^{2-1}\times r

⇒ a_{2} = a^{1}\times r

⇒ a_{2} = 612\times 1.08

⇒ a_{2} = 661

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