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kakasveta [241]
3 years ago
12

you roll two dice what is the probability that the sum of the dice is less than 5 and one dice shows a 2? ...?

Mathematics
1 answer:
astraxan [27]3 years ago
3 0
<span>Lets say the 1st die rolled a 2 - there would be 2 combinations for which the sum of dice being < 5 : 2,1 2,2 Now say the 2nd die rolled a 2 - there would be 2 combinations for which the sum of dice being < 5 : 1,2 2,2 Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice. So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5: 1,2 2,1 2,2 The total number of unique outcomes for two dice is 6*6=36 . So, the probability you are looking for is 3/36 = 1/12</span>
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Answer:

5000

Step-by-step explanation:


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3 years ago
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Greg and Erin start at the same point and begin running in different directions. Greg is running east at a speed of 7 miles per
AveGali [126]

Answer: The time at which the distance between the two is 150 miles is 1.3 hr.

Step-by-step explanation:

Step 1: Sketch the problem as shown in the attached image.

The problem can be solved using Pythagoras theorem since the sketch is a right angled triangle.

It follows the equation x² + y² = 15².

The distance covered by Greg is given by <em>x mi</em>, and that of Erin is given by <em>y mi</em>.

Step 2: To derive the distance covered by Erin and Greg, we use the formula <em>Speed = distance ÷ time.</em>

Which by cross-multiplying gives <em>distance = speed × time</em>.

Let time taken to cover the distance be <em>t h</em>.

Given that Speed of Erin is 9 mph and that of Greg is 7 mph.

Hence, distance covered by Greg, x = 7 × t = 7t.

Distance covered by Erin, y = 9 × t = 9t.

Step 3: Insert the terms x and y into the Pythagoras equation x² + y² = 15² and solve for <em>time t.</em>

(7t)² + (9t)² = 15²

49t² + 81t² = 225

(49 + 81)t² = 225

      t² = 225/(49 + 81)

      t² = 225/130

      t² = 1.730769231

       t = √1.730769231

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t = 1.3hr

Hence the time at which the distance between the two is 150 miles is 1.3 hr.

4 0
3 years ago
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Answer:

x=33\\y=-41

Step-by-step explanation:

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2x+y=25\hspace{5}(1)\\and\\4x+3y=9\hspace{5}(2)

We need to eliminate one of the variables, so let's use elimination method. First multiply (1) by 2

2*(1)\equiv\hspace{5}4x+2y=50

Now subtract (2) from 2*(1) in order to eliminate x:

2*(1)-(2)\\4x-4x+2y-3y=50-9\\-y=41

Solving for y:

Multiplying both sides by -1  

y=-41

Finally, replacing the value of y in (1)

2x-41=25

Solving for x:

add 41 to both sides:

2x=66

Multiply both sides by 1/2:

x=\frac{66}{2} =33

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\huge\boxed{\text{48 inches}}

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