Question

WILL MARK THE CORRECT ANSWER BRAINLIEST! Select all the correct answers:

Answer 1

Answer:

B, D

Step-by-step explanation:

Solve all equations:

A.

$x-3x=-2x+4\\ \\-2x=-2x+4\\ \\0=4$

This is false equality, so this equation has no solutions.

B.

$x-\dfrac{1}{3}(3x)=0\\ \\x-x=0\\ \\0=0$

This equality is true for all values of x, so this equation has infinitely many solutions.

C.

$\dfrac{1}{3}x-3=4+2x\\ \\x-9=12+6x\\ \\x-6x=12+9\\ \\-5x=21\\ \\x=-\dfrac{21}{5}$

This equation has the unique solution.

D.

$3x+2-\dfrac{1}{3}(3x)=2+2x\\ \\9x+6-3x=6+6x\\ \\6x+6=6+6x\\ \\0=0$

This equality is true for all values of x, so this equation has infinitely many solutions.

E.

$x-\dfrac{1}{3}x+2=0\\ \\3x-x+6=0\\ \\2x=-6\\ \\x=-3$

This equation has the unique solution.