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Reika [66]
2 years ago
14

WILL MARK THE CORRECT ANSWER BRAINLIEST! Select all the correct answers:

Mathematics
1 answer:
stepladder [879]2 years ago
8 0

Answer:

B, D

Step-by-step explanation:

Solve all equations:

A.

x-3x=-2x+4\\ \\-2x=-2x+4\\ \\0=4

This is false equality, so this equation has no solutions.

B.

x-\dfrac{1}{3}(3x)=0\\ \\x-x=0\\ \\0=0

This equality is true for all values of x, so this equation has infinitely many solutions.

C.

\dfrac{1}{3}x-3=4+2x\\ \\x-9=12+6x\\ \\x-6x=12+9\\ \\-5x=21\\ \\x=-\dfrac{21}{5}

This equation has the unique solution.

D.

3x+2-\dfrac{1}{3}(3x)=2+2x\\ \\9x+6-3x=6+6x\\ \\6x+6=6+6x\\ \\0=0

This equality is true for all values of x, so this equation has infinitely many solutions.

E.

x-\dfrac{1}{3}x+2=0\\ \\3x-x+6=0\\ \\2x=-6\\ \\x=-3

This equation has the unique solution.

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The zeros of the cubic function f(x) = 2x³ - 6x² - 16x - 20 are given as follows:

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The equation is defined by the rule presented as follows:

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Now we expand the right side to begin finding the coefficients of the quadratic function that we are going to solve to find the remaining zeros:

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Then these coefficients are obtained comparing the left and the right side of the equality as follows:

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The vertices of the polygon are A (3,5), B (6,5), C (6, 9), and D (3,9). Find the distance between the vertices B and C.
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