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svlad2 [7]
3 years ago
10

One hexagonal base and the other faces in the shape of triangles

Mathematics
1 answer:
frozen [14]3 years ago
6 0
What ? more info is needed please
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Picture of problem below NO LINKS
iragen [17]

Answer:

600$

Step-by-step explanation:

I think this is right

5 0
3 years ago
Point S is on line segment RT. Given RT=4x, ST = 5x-10, and RS = 6 determine the numerical length of ST.
Art [367]

Answer:

ST=10

Step-by-step explanation:

8 0
3 years ago
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
4 years ago
Nancy made 3 different stacks of wooden blocks. The first stack was 6 blocks high, the second
tensa zangetsu [6.8K]

Answer:30

Step-by-step explanation:6+9+15=30

6 0
3 years ago
Read 2 more answers
A club swimming pool is 21 ft wide and 33 ft long. the club members want an exposed aggregate border in a strip of uniform width
vovangra [49]
First compute the perimeter of the pool:
(21+33)*2=108 foot. 
Since the material cover 232 ft^2, then it is sufficient to divide the above number over the length of the border like this:
232/108=2.1

The trip can be 2.1 ft in wide. 
5 0
3 years ago
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