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3 years ago

What must be given to prove that CJG ~ CEA

1 answer:

4 0

1) if ∠J=∠E and ∠G=∠A ⇒ ΔCJG ~ ΔCEA
2) if ∠J=∠E and JC:JC=JG:EA ⇒ ΔCJG ~ ΔCEA
3) if JC:JC=JG:EA= CG:CA ⇒ ΔCJG ~ ΔCEA

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1 year ago

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2 years ago

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2 years ago

What’s the correct answer for this?

otez555 [7]

Answer:

0.7 + 0.4 - 0.2 = 0.9

Step-by-step explanation:

Let's denote the probabilities as following:

The probability that the show had animals is

P(A) = 0.7

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P(B) = 0.4

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2 years ago

Lol help anyone?PLEASE !!

Savatey [412]

Answer:

B: 1/5 = 4/x

Step-by-step explanation:

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2 years ago

Read 2 more answers