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DiKsa [7]
3 years ago
15

What must be given to prove that CJG ~ CEA

Mathematics
1 answer:
Karolina [17]3 years ago
4 0
1) if ∠J=∠E and ∠G=∠A ⇒ ΔCJG ~ Δ<span>CEA
2) </span>if ∠J=∠E and JC:JC=JG:EA ⇒ ΔCJG ~ Δ<span>CEA
3) </span>if JC:JC=JG:EA= CG:CA ⇒ ΔCJG ~ Δ<span>CEA</span>
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Math riddle here
kupik [55]

Answer:

15+8+6+2=31

Step-by-step explanation:

highest no. is 15

15-7=8

31-15-8=8

middle number 8

8-6=2

CHECK: 15+8+6+2=31

i don't know if my answer is right haha

i checked online it says the answer is 5,6,8,12

4 0
2 years ago
A jacket originally cost $30.75. It went on sale for 20% off the original price. What was the sale price of the jacket?
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The sale price of the jacket was $6.15.
6 0
3 years ago
X-2=3(x-4) what is the solution
Vladimir [108]
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8 0
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Read 2 more answers
The gable end of the roof shown is divided in half by a vertical brace. Find the distance h (in ft) from an eave to the peak. 41
nlexa [21]

Answer:

h = 9 ft  

Step-by-step explanation:

Assume the diagram is like the one below.

∆ABD is a right triangle.

We can use Pythagoras' Theorem to find the height h.

\begin{array}{rcl}h^{2} + 40^{2} & = & 41^{2}\\h^{2} + 1600 & = & 1681\\h^{2} & = & 1681 - 1600\\& = &81\\h& = & \sqrt{81}\\&=& \mathbf{9}\end{array}\\\text{The height of the gable is $\large \boxed{\textbf{9 ft}}$}

 

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3 years ago
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Ket [755]
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3 0
3 years ago
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