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Softa [21]
3 years ago
14

There is a bag filled with 5 blue and 6 red marbles.

Mathematics
1 answer:
Lorico [155]3 years ago
5 0

There are 6+5 marbles.

Of those, 5 are red.

The chances of drawing a red marble are 5/11

Since you replace the marble you drew, the chances each draw remain 5/11

You cannot draw two red marbles without drawing a red marble on your first draw, so the odds of you making a second draw are 5/11. The odds of that also being red are 5/11… but we only care about that 5/11ths the time

5/11*5/11=25/121

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3/4ths multiplied by x equals 4 7/8ths what is x
alexandr402 [8]

Answer:

x=13/2

Step-by-step explanation:

3/4x=4 7/8

x= 4 7/8 divided by 3/4

x=13/2

check

3/4*13/2=39/8

=4 7/8

7 0
3 years ago
I need help :,)
Dmitry_Shevchenko [17]

Answer:

add 17.50 to 8.75 you get 26.25

7 0
2 years ago
Read 2 more answers
Consider the toss of four coins. There are 16 (i.e., 24) possible outcomesin one toss. (a)Calculate the probabilities that there
lana [24]

Answer:

See answers below

Step-by-step explanation:

If 4 coins are tossed. the total possible outcomes are;

H H H H , H H H T, H H T H, H T H H, T H H H , H H T T, H T T H, T T H H, H T H T, T H T H, T H H T , H T T T, T H T T, T T H T, T T T H  and T T T T

Total outcomes = 16

1) zero head = T T T T = 1 outcome

Probability = Expected/Total outcome

Pr(zero head) = 1/16

2) one head = H T T T, T H T T, T T H T, T T T H   = 4 outcomes

Probability = Expected/Total outcome

Probability = 4/16

Pr(one head) = 1/4

3) two heads = H H T T, H T T H, T T H H, H T H T, T H T H, T H H T   = 6 outcomes

Probability = Expected/Total outcome

Pr(two head) = 6/16

Pr(two head) = 3/8

4)  three heads = H H H T, H H T H, H T H H, T H H H   = 4 outcomes

Probability = Expected/Total outcome

Pr(three heads) = 4/16

Pr(two head) = 1/4

5) four heads appearing on the four coins =  H H H H = 1 outcome

Pr(four heads) = 1/16

6 0
3 years ago
A line segment of length k is divided into 3 equal parts what is the distance between midpoints of the first and third segments
anastassius [24]

Line segment of length k is divided into 3 equal parts.

so first segment is 0-k/3 and third segment is 2/3k-k

so mid-pt of 1st = k/6 and 3rd = 5/6k

so the distance in between = 5/6k-k/6 = 4/6k = 2/3k

4 0
3 years ago
How to change 0.225 into a fraction
Aloiza [94]
I believe it’s 9/30
8 0
3 years ago
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