Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at a ratio of 7, thus 3:7,
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, that satisfy two conditions:
ac=jk and b=j+k in this case:
ac=jk=-18 and b=j+k=7 so j and k must be 9 and -2
Now replace bx with jx and kx in the original equation...
x^2-2x+9x-18 and factor the 1st and 2nd pair of terms...
x(x-2)+9(x-2) which is equal to
(x+9)(x-2)
Answer:
it's hypotenuse
then
base^2+length ^2=hypotenuse^2
5^2+9^2=106^2
11236
if wrong correct me pls
have a great day ahead
CapTainGeNius
Answer:
hi the answer would be x= -1 14/15
