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slega [8]
3 years ago
11

A project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Complete question:

A project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability

distribution below?

Grade(X)_____ 1_____2_____3_____4_____5

Frequency____3 _____5____ 9 ____ 5 ____ 3

P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1

Answer:

3

Step-by-step explanation:

Given the probability distribution :

Grade(X)_____ 1_____2_____3_____4_____5

Frequency____3 _____5____ 9 ____ 5 ____ 3

P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1

The mean of the distribution :

Σ(X * P(X)) :

(1*0. 1) + (2 * 0.2) + (3 * 0.4) + (4 * 0.2) + (5 * 0.1)

0.1 + 0.4 + 1.2 + 0.8 + 0.5

= 3

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An automobile dealer wants to see if there is a relationship between monthly sales and the interest rate. A random sample of 4 m
SVETLANKA909090 [29]

Answer:

a) y=-6.254 x +75.064  

b) r =-0.932

The % of variation is given by the determination coefficient given by r^2 and on this case -0.932^2 =0.8687, so then the % of variation explained by the linear model is 86.87%.

Step-by-step explanation:

Assuming the following dataset:

Monthly Sales (Y)     Interest Rate (X)

       22                               9.2

       20                               7.6

       10                                10.4

       45                                5.3

Part a

And we want a linear model on this way y=mx+b, where m represent the slope and b the intercept. In order to find the slope we have this formula:

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=278.65-\frac{32.5^2}{4}=14.5875  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=696.9-\frac{32.5*97}{4}=-91.225  

And the slope would be:  

m=\frac{-91.225}{14.5875}=-6.254  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{32.5}{4}=8.125  

\bar y= \frac{\sum y_i}{n}=\frac{97}{4}=24.25  

And we can find the intercept using this:  

b=\bar y -m \bar x=24.25-(-6.254*8.125)=75.064  

So the line would be given by:  

y=-6.254 x +75.064  

Part b

For this case we need to calculate the correlation coefficient given by:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

r=\frac{4(696.9)-(32.5)(97)}{\sqrt{[4(278.65) -(32.5)^2][4(3009) -(97)^2]}}=-0.937  

So then the correlation coefficient would be r =-0.932

The % of variation is given by the determination coefficient given by r^2 and on this case -0.932^2 =0.8687, so then the % of variation explained by the linear model is 86.87%.

6 0
3 years ago
What is the exact circumference of a circle with a radius of 12 inches?
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We can get the circumference of any circle in terms of the radius with this formula. C = 2\pir.

Where r is the radius of the circle.

And we will use 3.14 for \pi.

Plug in all the values.

C = 2 * 3.14 * 2

C = 12.56

So, the circumference of the circle is 12.6 inches when rounded to the nearest tenth.
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Answer:

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