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Afina-wow [57]
3 years ago
8

Please solve and show steps for both 23 and 24

Mathematics
1 answer:
const2013 [10]3 years ago
3 0
23. The answer is D. If you multiply 0.8 by 5 you get 4 meters which means it would take 5 minutes. Multiplying it by 5 will give you a whole number therefore easier to find on the graph.

24. The answer is G. The square root of 5 is 2.23 and the square root of 2 is 1.4
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Simplified expression -6x+2/3(9-15x)-2
Artist 52 [7]

Answer:

-16x+4

Step-by-step explanation:

-6x+2/3(9-15x)-2

Distribute

-6x +2/3 *9 +2/3*(-15x) -2

-6x +6 -10x -2

Combine like terms

-6x-10x +6-2

-16x+4

7 0
3 years ago
Write the equation of a line that is perpendicular to y=-2x/7+9 and that passes through the point (4,−6)
Shtirlitz [24]

Answer:

  y = (7/2)x -20

Step-by-step explanation:

The given line is in slope-intercept form, so you can read its slope from the equation.

  y = mx + b . . . . . m is the slope; b is the y-intercept

  y = -(2/7)x + 9 . . . . . . has slope -2/7

The perpendicular line will have a slope that is the negative reciprocal of this, so will be ...

  m = -1/(-2/7) = 7/2

We can use this and the given point to write the equation in point-slope form.

  y = m(x -h) +k . . . . . . line with slope m through point (h, k)

We have m = 7/2, (h, k) = (4, -6) so the equation is ...

  y = (7/2)(x -4) -6

  y = (7/2)x -20

4 0
3 years ago
X^2-x-56=0 <br> How do you use the zero product property to solve this?
S_A_V [24]

Answer:

(x - 8) (x + 7)

x = 8 or x = -7

6 0
3 years ago
Read 2 more answers
Which equation represents y = −x2 + 6x + 7 in vertex form? y = −(x + 3)2 + 4 y = −(x − 3)2 + 10 y = −(x + 3)2 + 2 y = −(x − 3)2
Colt1911 [192]

\text{The vertex form:}\ y=a(x-h)^2+k\\\\f(x)=ax^2+bx+c\to h=\dfrac{-b}{2a},\ k=f(h)\\\\\text{We have}\ y=-x^2+6x+7\to f(x)=-x^2+6x+7\\\\a=-1,\ b=6,\ c=7\\\\h=\dfrac{-6}{2(-1)}=\dfrac{-6}{-2}=3\\\\k=f(3)=-3^2+6(3)+7=-9+18+7=16\\\\Answer:\ \boxed{y=-(x-3)^2+16}

8 0
3 years ago
What is 946 divided by 11?
timama [110]
Answer: 946 ∻ 11 = 86


3 0
3 years ago
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