Lets first reduce 12/20....12/20 = 3/5
5/3 + 3/5 = 25/15 + 9/15 = 34/15 or 2 4/15
Dude, what kind of question is this??? Here's my best shot.
If they start at the 32-mile mark, then the we can use 32 as the intercept. 50 can be the change in position over time, so
y=50x+32 (?)
225125₆/101₆ = 2225₆
One way to arrive at this is to convert both given numbers to base 10, compute the quotient in base 10, then convert back to base 6.
101₆ = 1×6² + 0×6¹ + 1×6⁰ = 37
225125₆ = 2×6⁵ + 2×6⁴ + 5×6³ + 1×6² + 2×6¹ + 5×6⁰ = 19,277
So we have
225125₆/101₆ = 19,277/37 = 521
Next,
521 = 2×216 + 89 = 2×6³ + 89
89 = 2×36 + 17 = 2×6² + 17
17 = 2×12 + 5 = 2×6¹ + 5×6⁰
and so
521 = 2×6³ + 2×6² + 2×6¹ + 5×6⁰ = 2225₆
Or you can use the long division algorithm. Division in base 6 is the same as in base 10, except numerals range from 0 to 5 instead of 0 to 9. See if you can follow this diagram (replaced with an attachment)
ANSWER: THE SOLUTION OF GIVEN INEQUALITIES IS ALL REAL NUMBER EXCEPT [1.167,3.5].
Answer:
Step-by-step explanation:
The nth term for a geometric sequence is given by :-
(1)
We are given that The first term in a geometric sequence is 54. i.e. a=54
5th term= (2)
Put n=5 and a= 54 in (1), we get
(3)
From (2) and (3), we have
Explicit form for the geometric sequence: