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3 years ago

When x pounds of force is applied to one end of a lever that is L feet long, the resulting force y on the other end is

1 answer:

3 0

The question is worded poorly, but it looks like you have a lever in equilibrium, with a force x at a distance d from the fulcrum, and a force y at a distance L - d from the fulcrum. You already have the equilibrium formula for this situation:

xd = y(L - d)

If you know x, y, and d, you can solve for the length L.

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A rectangle porch is 4 feet wide. It is 3 times long as it is wide

Alexeev081 [22]

Label the width: 4ft
Label the length: 12ft (4ft for each segment).
Perimeter=12+12+4+4=32ft

7 0

3 years ago

Read 2 more answers

\frac{3}{4} \times 2 =

suter [353]

To multiply two fractions, you simply multiply numerators and denominators together.

2 can be read as the fraction 2/1

So, the multiplication is

$\dfrac{3}{4} \times \dfrac{2}{1} = \dfrac{3\times 2}{4 \times 1} = \dfrac{6}{4} = \dfrac{3}{2}$

8 0

3 years ago

Which of the following functions is represented by the graph below?

Ann [662]

Answer:

A. y = 3 cos (1/2) x.

Step-by-step explanation:

The y-intercept is 3 so it will contain 3 cos x (because y = cos x passes through (0, 1).

The graph of 3 cos x has been stretched horizontally by a factor 2 ( 3 cos x would pass through (π/2, 0) whereas the given graph passes through (π, 0).

So the equation is 3 cos(1/2) x

6 0

3 years ago

2a+3b=5? What is that someone please help ASAP !!

AnnyKZ [126]

Answer:

subtract 2a + 3b - 3b =5 - 3b

simply 2a = 5 -3b

divide both sides by 2 . 2a over 2 = 5 over 2 - 3b over 2

simply a= 5- 3b over 2

5 0

3 years ago

Please show your work.

levacccp [35]

The amount of money you have is $ 20864.521

<h3>Solution:</h3>

Given that you invested $15,000 dollars for 11 years at 3% annual interest compounded continuously.

To find: total amount of money

The compound interest formula for compounded continously is given as:

$A = p e^{rt}$

Where "p" is the principal

"r" is the rate of interest

"t" is the number of years

Here in this problem, p = 15000

t = 11 years

$r = 3 \% = \frac{3}{100} = 0.03$

Substituting the values in formula we get,

$A = 15000e^{0.03 \times 11}\\\\A = 15000e^{0.33}\\\\A = 15000 \times 1.390968\\\\A = 20864.521$

Thus the amount of money you have is $ 20864.521

5 0

3 years ago