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krok68 [10]
2 years ago
8

7. x – 5y = 42x + 14 = y​

Mathematics
1 answer:
const2013 [10]2 years ago
4 0
This is your answer.... all you are doing is substituting what ever the variable is

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What is the solution to this equation x -9=5​
lukranit [14]

Answer:

x = 14

Step-by-step explanation:

x- 9 = 5

Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. Add 9 to both sides of the equation:

x - 9 (+9) = 5 (+9)

x = 5 + 9

x = 14

x = 14 is your answer.

~

7 0
3 years ago
How many ways can an 8-question True/False quiz be answered
tresset_1 [31]

Answer:

256

Step-by-step explanation:

two choices for each question so

2^8=256

3 0
3 years ago
A bag contains white marbles and green marbles, 117 in total. The number of white marbles is 9 more than 5 times the number of g
SashulF [63]

Answer:

that is the solution to the question

4 0
3 years ago
2 eight and eleven hundredths as a decimal
german

Answer:

28.11

Step-by-step explanation:

6 0
3 years ago
The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle
ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.

Hence, the length is 2w+6.

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

A=w(2w+6)

We can also substitute 40 in for A as it's given in the question.

40 = w(2w+6)

Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get

40 = 2w^2+6w

We can make the equation simpler by dividing both sides by 2.

20 = w^2+3w

Subtracting both sides by 20 will make the left-hand side 0.

0=w^2+3w-20

Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}

w= \frac{-3\pm\sqrt{9+80}}{2}

w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}

Since the second solution results in a negative number, it cannot be the length of w.

w=\frac{-3+\sqrt{89}}{2}\approx3.217

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

l=2(3.217)+6

l=12.434

The length of this rectangle is 12.434 cm.

6 0
1 year ago
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