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Veseljchak [2.6K]
3 years ago
12

Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, what is the greatest numb

er of rides Daniel can go on?
Mathematics
2 answers:
mote1985 [20]3 years ago
8 0
25= 1.50x+4
Subtract 4
21= 1.50x
Divide by 1.50
X=14 rides or less
Norma-Jean [14]3 years ago
7 0
The greatest number of rides he can go = ($25-$4)/$1,50=14
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Simplify.

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Answer:

B. 9 < 10,  

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Step-by-step explanation:

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B. 9 < 10,   true  9 is less than 10

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Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.

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Answer:

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Step-by-step explanation:

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3 years ago
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