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Leni [432]
3 years ago
6

Write a statement that outputs variable numObjects. End with a newline.

Computers and Technology
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

The code is witten in Java and given in the explanation section.

Using a Scanner object we receive a the user's input and with the System.out.println we output the variable

Explanation:

import java.util.Scanner;

public class VariableOutput{

   public static void main (String [] args){

       Scanner input = new Scanner(System.in);

       System.out.println("Enter an Integer 15 or 40");

       int numObjects = input.nextInt();

       System.out.println("You entered the number "+numObjects);

   }

}

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Also, the processor core has to be put into consideration, Daniel will need a multi - core processor in other to aid the smooth running of his racing game.

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2 years ago
I don't understand how to write code for this in Java using nested for loops only. The official question is: write a program tha
Bingel [31]

Answer:

public class Triangle

{

public static void main( String[] args )

{

show( 5 );

}

public static void show( int n )

{

int i,j,k;

for (i = 0; i < n - 1; i++ )

{

for (j = 0; j < i; j++ )

{

System.out.print( " " );

}

for (k = n - i; k > 0; k-- )

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System.out.print( "* " );

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System.out.println();

}

for (i = 0; i < n; i++ )

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for (j = n - i; j > 1; j-- )

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System.out.print( " " );

}

for (k = 0; k < i + 1; k++ )

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System.out.print( "* " );

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System.out.println();

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4 0
3 years ago
How did hitles rules in nazi germany exemplify totiltarian rule?
ddd [48]

Answer:

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7 0
3 years ago
Convert infix to postfix
kvv77 [185]

Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

 

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

 

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

 

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;    

else

operators.pop();

}

else

{

while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

operands.push(operators.pop());

operators.push(c);

}

}

while (!operators.isEmpty())

operands.push(operators.pop());

while (!operands.isEmpty())

calculation+=operands.pop();

calculation=calculation.reverse();

return calculation;

}

Explanation:

  • Create the checkSymbol function to see what symbol is being passed to the stack.
  • Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
  • Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
  • While the operators is  not empty, keep pushing the character to the operators stack.
  • At last reverse and return the calculation which has all the results.
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