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Leni [432]
3 years ago
6

Write a statement that outputs variable numObjects. End with a newline.

Computers and Technology
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

The code is witten in Java and given in the explanation section.

Using a Scanner object we receive a the user's input and with the System.out.println we output the variable

Explanation:

import java.util.Scanner;

public class VariableOutput{

   public static void main (String [] args){

       Scanner input = new Scanner(System.in);

       System.out.println("Enter an Integer 15 or 40");

       int numObjects = input.nextInt();

       System.out.println("You entered the number "+numObjects);

   }

}

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NumA = 3 <br>numB = 2<br>Result = numA ** numB
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The result of the following code will be 9

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There are several operators used in Python to do mathematical calculations.

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2 years ago
Find the inverse function of f(x)= 1+squareroot of 1+2x
Svetllana [295]

Answer:

Therefore the inverse function of  f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

Explanation:

We need to find the inverse of function f(x)=1+\sqrt{1+2x}

Function Inverse definition :

\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}

y=1+\sqrt{1+2x}\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y

x=1+\sqrt{1+2y}

\mathrm{Solve}\:x=1+\sqrt{1+2y}\:\mathrm{for}\:y

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+\sqrt{1+2y}-1=x-1

Simplify

\sqrt{1+2y}=x-1

\mathrm{Square\:both\:sides}

\left(\sqrt{1+2y}\right)^2=\left(x-1\right)^2

\mathrm{Expand\:}\left(\sqrt{1+2y}\right)^2:\quad 1+2y

\mathrm{Expand\:}\left(x-1\right)^2:\quad x^2-2x+1

1+2y=x^2-2x+1

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+2y-1=x^2-2x+1-1

\mathrm{Simplify}

2y=x^2-2x

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2y}{2}=\frac{x^2}{2}-\frac{2x}{2}

\mathrm{Simplify}

y=\frac{x^2-2x}{2}

Therefore the inverse function of f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

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