Answer:
This is a radioactive decay / half-life problem.
Initial amount of C 14 = 100% Present Amount = 57%
k = .0001 (that value should be negative)
Nt = No * e^ (k*t)
You need to solve that equation for "time" (equation attached)
time = natural log (Ending amount / Starting Amount) / k
time = natural log (57% / 100%) / -.0001
time = ln (.57) / -.0001
time = -.56211891815 / -.0001
time = 5,621.2 years (age of the bird skeleton)
These problems are quite complicated but I think I know this pretty well.
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Step-by-step explanation:
Answer:
De value of k is 9
Step-by-step explanation:
6,-1
b(1,3)
(k,8)
am using bodmas
a6-1×1=6a
b1×3=3b
abc=8
6a+3b+8=17-8
=9
Answer:
5/7
Step-by-step explanation:
y2-y1/x2 -x1
3 - (-2)/9-2
3+2/9-2
5/7
Answer:
x = 40/3
Step-by-step explanation:
2/3 = (8/x) + 6
-6 -6
2/3 - 6 = -16/3
-16/3 = 8/x
*x *x
(-16/3)x = 8
+16/3 +16/3
x = 40/3