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Ira Lisetskai [31]
3 years ago
15

Please I need help I mark brainliest!

Mathematics
1 answer:
jeyben [28]3 years ago
8 0

Answer:

C) Subtract the sum 15 and 12 from 40

Step-by-step explanation:

15 + 12 = 27

40 - 27 = 13

Therefore Monica's change would be $13.

Hope this helps! :)

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Find the area of the triangle. A= 125°, b= 9, c= 6
Semmy [17]

The area of given triangle is: 22.1184

Step-by-step explanation:

When we only know two sides of a triangle and the included angle then the area of triangle is given by:

A = \frac{1}{2} * side\ 1 * side\ 2 * angle

Given

b = 9

c = 6

∠A = 125°

So the formula will be:

A = \frac{1}{2} bc * sin\ A\\A = \frac{1}{2} * 9 * 6 * sin\ 125\\A = 27 * 0.8192\\A = 22.1184

Hence,

The area of given triangle is: 22.1184

Keywords: Triangle, Area

Learn more about triangle at:

  • brainly.com/question/4706270
  • brainly.com/question/4710621

#LearnwithBrainly

6 0
3 years ago
HELP ASAP NO ROCKY PLEASE​
bixtya [17]

m<1 is 50

m<2 is 130

m<3 is 50

m<4 is 130

m<5 is 40

m<6 is 140

m<7 is 90

m<8 is 140

WELCOME TO AUSTIN TEXAS ASAP LMFMSMSNS BYE

7 0
3 years ago
Read 2 more answers
I do not know how to solve this problem or know what to do with the exponents
horsena [70]
K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also
(ab)^c=(a^c)(b^c)
and
x^{-m}= \frac{1}{x^m}
and
x^ \frac{m}{n}= \sqrt[n]{x^m}
and
( \frac{x}{y} )^m= \frac{x^m}{y^m}
and
(x^m)^n=x^{mn}
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)


so
( \frac{-7x^ \frac{3}{2} }{5y^4} )^{-2}=
( \frac{-7}{5} )^{-2}( \frac{x^ \frac{3}{2} }{y^4} )^{-2}=
( \frac{(-7)^{-2}}{5^{-2}} )( \frac{(x^ \frac{3}{2})^{-2} }{(y^4)^{-2}} )=
( \frac{ \frac{1}{(-7)^2} }{ \frac{1}{5^2} } )( \frac{x^ \frac{-6}{2} }{y^{-8}} )=
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{(x^{-3}) }{\frac{1}{y^8}} )
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{\frac{1}{x^3} }{\frac{1}{y^8}} )=
(\frac{25}{49} )( \frac{y^8}{x^3}=
\frac{25y^8}{49x^3}
4 0
3 years ago
A pool measuring 8 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the poo
Ainat [17]
Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.

Combined Area = (2x + 26)*(2x + 8) = 1008

2x*(2x + 8) + 26*(2x + 8 ) = 1008

4x² + 16x + 52x + 208 = 1008

4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0.          Divide through by 4.
x²  + 17x - 200 = 0 . This is a quadratic equation.

Multiply first and last coefficients:  1*-200 = -200

We look for two numbers that multiply to give -200, and add to give +17

Those two numbers are 25 and -8.

Check:   25*-8 = -200         25 + -8 = 17

We replace the middle term of +17x in the quadratic expression with 25x -8x


 x² +17x - 200 = 0     

x² + 25x - 8x - 200 = 0     

x(x + 25) - 8(x + 25) = 0

(x+25)(x -8) = 0

x + 25 = 0    or   x - 8 = 0

x = 0 -25              x = 0 + 8

x = -25                    x = 8

The width of the path can not be negative.

The only valid solution is x = 8.

The width of the path is 8 meters.
8 0
3 years ago
Solve: I -12 I - I 3 I =
Alborosie

Answer: A

Step-by-step explanation:

-12 is made positive so the equation is turned to 12-3 which is 9

8 0
3 years ago
Read 2 more answers
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