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viktelen [127]
4 years ago
8

julia is standing 2 feet away away from a lamppost. she casts a shadow of 5 feet and the light make a 20 degree angle relative t

o the ground from the top of her shadow. Does the expression give you the height of the lamppost

Mathematics
1 answer:
NikAS [45]4 years ago
3 0

Height of the lamp post is 2.5 ft.

<u>Step-by-step explanation:</u>

AB = lamp post

CD = Julia

CE = Shadow

AC = 2 ft , CE = 5 ft , ∠AEB = 20°

AE = AC+ CE = 2+ 5 = 7 ft

Considering ABE as a right triangle, we can write the tan ratio as,

tan ∠AEB = opp/adj = AB/AE

AB = AE × tan ∠AEB

    = 7 × tan 20°

  = 2.5 ft

So, height of the lamp post is 2.5 ft.

<u></u>

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Find the 73rd of the sequence -1, 5, 11,...
Aleksandr-060686 [28]

Answer:

431

Step-by-step explanation:

This is an arithmetic sequence with first term a₁ = -1 and common difference d = 6.

The nth term of an arithmetic sequence is:

a = a₁ + d (n − 1)

The 73rd term is:

a = -1 + 6 (73 − 1)

a = 431

4 0
4 years ago
HURRRY! ILL GIVE BRAINLEST Mrs. Jordan surveyed all of her students to find out which testing format they prefer. Of the 120 stu
taurus [48]

Answer:

50%

Step-by-step explanation:

30+10=40

40+20=60

120-60=60

60 is 50% of 120

3 0
3 years ago
Read 2 more answers
Benny invests $960 yearly into an account that pays 8% interest, compounded
docker41 [41]

Answer:

$2,072.56

Step-by-step explanation:

Compound interest formula is expressed as;

A = P(1+r) ^ n

A = 960(1+0.08) ^ 10

A = 960(1.08)^10

A = 960(2.1589)

A = 2,072.56

Hence the amount in Benny's account after 10 years is $2,072.56

7 0
3 years ago
The lines graphed below are parallel. The slope of the red line is - What is
PIT_PIT [208]

Answer:

C. -4/3

Step-by-step explanation:

Parallel lines have the same gradient (steepness) and this means that they will never intersect.

Hope this helps!

7 0
3 years ago
2. Using Vièta's theorem, find the solutions to the equation. a) x^2 - 3x + 2 = 0 b) x^2 + 2x - 15 = 0.
olga_2 [115]

Given:

\begin{gathered} x^2-3x+2=0 \\ x^2+2x-15=0 \end{gathered}

Required:

We need to find the solution by Vièta's theorem.

Explanation:

Compare 1st equation with

ax^2+bx+c=0

we get

\begin{gathered} a=1 \\ b=-3 \\ c=2 \end{gathered}

Vièta's theorem is

\begin{gathered} x_1+x_2=-\frac{b}{a} \\ x_1x_2=\frac{c}{a} \end{gathered}

\begin{gathered} x_1+x_2=3 \\ x_1x_2=2 \end{gathered}

now solve this equation and we get

\begin{gathered} x_1=1 \\ x_2=2 \end{gathered}

because addition of 1 and 2 is 3 and multiplication is 2

Now for 2nd equation

\begin{gathered} a=1 \\ b=2 \\ c=-15 \end{gathered}

apply Vièta's theorem

\begin{gathered} x_1+x_2=-2 \\ x_1x_2=-15 \end{gathered}

by this

\begin{gathered} x_1=3 \\ x_2=-5 \end{gathered}

because addition of 3 and -5 is -2 and multiplication is -15

8 0
1 year ago
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