First we need to have same units before comparing them. That is, either both of them are in cm or both of them are in mm. So if we need to convert 12.5 cm to mm, we know that 1 cm =10 mm. So we have to find out how many mm are in 12.5 cm. And let 12.5 cm =x mm. So to find the value of x , we set a proportion and solve for x. That is

The units cancel out and we do cross multiplication. That is

x=125
So 12.5 cm =125 mm. Therefore the correct proportion is C.
4 because you would say "forty three thousand..." three would be the one thousands place, and 4 would be the ten thousands place.
Answer:
The data table is attached below.
Step-by-step explanation:
The average of a set of data is the value that is a representative of the entire data set.
The formula to compute averages is:

Compute the average for drop 1 as follows:
![\bar x_{1}=\frac{1}{3}\times[10+11+9]=10](https://tex.z-dn.net/?f=%5Cbar%20x_%7B1%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B10%2B11%2B9%5D%3D10)
Compute the average for drop 2 as follows:
![\bar x_{2}=\frac{1}{3}\times[29+31+30]=30](https://tex.z-dn.net/?f=%5Cbar%20x_%7B2%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B29%2B31%2B30%5D%3D30)
Compute the average for drop 3 as follows:
![\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33](https://tex.z-dn.net/?f=%5Cbar%20x_%7B3%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B59%2B58%2B61%5D%3D59.33)
Compute the average for drop 4 as follows:
![\bar x_{4}=\frac{1}{3}\times[102+100+98]=100](https://tex.z-dn.net/?f=%5Cbar%20x_%7B4%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B102%2B100%2B98%5D%3D100)
Compute the average for drop 5 as follows:
![\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67](https://tex.z-dn.net/?f=%5Cbar%20x_%7B5%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B122%2B125%2B127%5D%3D124.67)
The data table is attached below.
Hello!
I believe the next term in the velocity sequence should be 28 cm.