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Alexus [3.1K]
3 years ago
12

What is a common factor of 18x+24x+46?

Mathematics
2 answers:
statuscvo [17]3 years ago
4 0

Answer:

<h2>The common factor of 18x+24x+46 is <em><u>2</u></em></h2>

Step-by-step explanation:

The factors of 18 are:

18, 9, 6, 3, <em>2, 1</em>

The factors of 46 are:

46, 23, <em>2, 1</em>

The factors of 24 are:

<em>1, 2</em>, 3, 4, 6, 8, 12 and 24

Hope this helps

tatyana61 [14]3 years ago
3 0
2 is the greatest common factor.
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Convert 10x + 2y = 30 to slope intercept form by solving for y.
Tems11 [23]

Answer:

y = -5x + 15

Step-by-step explanation:

10x + 2y = 30

Subtract 10x from both sides.

2y = -10x + 30

Divide both sides by 2.

y = -5x + 15

6 0
3 years ago
What is the series in sigma notation? -5 + (-1) + 3 + 7 + 11?
EleoNora [17]
For the series:
- 5 + ( - 1 ) + 3 + 7 + 11
common difference between the numbers is 4 and a 1 = -5
The series in sigma notation:
  4
  ∑   ( 4 i - 5 )
i =0
7 0
3 years ago
if it rains tomorrow, the probability is 0.8 that john will practice the piano. if it does not rain tomorrow, there is only a .4
olga nikolaevna [1]
P(J / R) = P (J and R) / P(R) 
<span>0.8 = P (J and R) / 0.6 </span>
<span>P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining] </span>

<span>P(J / NR) = P (J and NR) / P(NR) </span>
<span>0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4 </span>
<span>P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining] </span>

<span>Hence; </span>
<span>Propability of John practicing regardless of weather condition is </span>

<span>P(John Practicing) = 0.48 + 0.16 = 0.64</span>
6 0
3 years ago
Read 2 more answers
Which equation has the correct sign on the product?
irakobra [83]
C. 25(-5) = 125 this is the answer
6 0
4 years ago
NFL Pre-Season Teams in the National Football League (NFL) in the US play four pre-season games each year before the regular sea
Mazyrski [523]

Answer:

H0 : ρ = 0

H1 : ρ ≠ 0

Test statistic = 1.197

Pvalue = 0.2335

There is no correlation between the two variables

Step-by-step explanation:

The null and alternative hypothesis :

H0 : No correlation exist,

H1 : Correlation exist

H0 : ρ = 0

H1 : ρ ≠ 0

Test statistic, T = r / √(1 - r²) / (n - 2)

T = 0.067 / √(1 - 0.067²) / (320 - 2)

T = 0.067 / √(0.995511 / 318)

T = 0.067 / 0.0559512

T = 1.197

The Pvalue obtained from the Rscore, at df = 320 - 2 = 318 is 0.2335

α = 5% = 0.05

The Pvalue > α ; we fail to reject the null and conclude that, there is no correlation between the two variables.

6 0
3 years ago
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