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Nezavi [6.7K]
3 years ago
6

L.F. Richardson proposed a model to describe the spread of war fever. His proposal: If y(t) is the percent of the population adv

ocating war at time t, then the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war. Set up a differential equation that is satisfied by y(t). (Note: Use k for the constant of proportionality with k > 0.)y' = ____________ , k > 0
Mathematics
1 answer:
Lena [83]3 years ago
8 0

Answer:

y'(t)=ky(t)(100-y(t))

Step-by-step explanation:

The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)

If y(t) is the percent of the population advocating war at time t

then 100-y(t)  is the percent of the population not advocating war

The product of the percentage of the population advocating war and the percentage not advocating war would be

y(t)(100-y(t))

If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then

y'(t)=ky(t)(100-y(t))

where <em>k is the constant of proportionality </em>

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Which theorem or postulate justifies that angle HEF ~ angle HGE ?
Levart [38]
Based on the picture above,
The theorem or postulate that justifies that Angle HEF ~ angle HGE is :
A. AA similarity postulate
(s is used for equal side, that is used for congruent)

hope this helps
5 0
3 years ago
If a polynomial function f(x)has root -2 + square root 8 and 9 what must be a factor of f(x)
Rasek [7]

Answer:

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

Step-by-step explanation:

Given that f(x) is a polynomial function.

This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.

Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)

i.e. If -2+\sqrt{8} is a root, then -2-\sqrt{8} is also a root.

(Because this only when multiplied will make coefficients rational)

So the factors of f(x) should be atleast

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

There can be other factors also but this is compulsory

7 0
3 years ago
Find the area of a trapezoid with base 1 side = 10 base 2 side = 16 and 3​
mart [117]

Answer:

Area of Trapezoid is 39 unit²

Step-by-step explanation:

Given as :

For A Trapezoid

The measure of base side 1 = b_1 = 10 unit

The measure of base side 2 = b_2 = 16 unit

The height of the Trapezoid = h = 3 unit

Let  The Area of Trapezoid = A square unit

<u>Now, From Formula</u>

Area of Trapezoid = \dfrac{1}{2} × (sum of opposite base) × height

I.e A =  \dfrac{1}{2} × (b_1 + b_2) × h

Or, A =  \dfrac{1}{2} × (10 unit + 16 unit) × 3 unit

Or, A =  \dfrac{1}{2} × (26 unit) × 3 unit

Or, A =  \dfrac{1}{2} × 78 unit²

Or, A = \dfrac{78}{2} unit²

I.e A = 39 unit²

So, The Area of Trapezoid = A = 39 unit²

Hence, The Area of Trapezoid is 39 unit² . Answer

6 0
3 years ago
Savannah loves to talk on her cell phone . she has $100 in her budget to pay this month's cell phone bill. her cell phone plan i
Serhud [2]

Answer:

200 minutes

Step-by-step explanation:

$20/$0.10=200

3 0
3 years ago
Points N and R both lie on circle O. Line segment RQ is tangent to the circle at point R.
4vir4ik [10]

Answer:

15.0

Step-by-step explanation:

Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.

The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)

4 0
3 years ago
Read 2 more answers
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