Based on the picture above,
The theorem or postulate that justifies that Angle HEF ~ angle HGE is :
A. AA similarity postulate
(s is used for equal side, that is used for congruent)
hope this helps
Answer:

Step-by-step explanation:
Given that f(x) is a polynomial function.
This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.
Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)
i.e. If
is a root, then
is also a root.
(Because this only when multiplied will make coefficients rational)
So the factors of f(x) should be atleast

There can be other factors also but this is compulsory
Answer:
Area of Trapezoid is 39 unit²
Step-by-step explanation:
Given as :
For A Trapezoid
The measure of base side 1 =
= 10 unit
The measure of base side 2 =
= 16 unit
The height of the Trapezoid = h = 3 unit
Let The Area of Trapezoid = A square unit
<u>Now, From Formula</u>
Area of Trapezoid =
× (sum of opposite base) × height
I.e A =
× (
+
) × h
Or, A =
× (10 unit + 16 unit) × 3 unit
Or, A =
× (26 unit) × 3 unit
Or, A =
× 78 unit²
Or, A =
unit²
I.e A = 39 unit²
So, The Area of Trapezoid = A = 39 unit²
Hence, The Area of Trapezoid is 39 unit² . Answer
Answer:
200 minutes
Step-by-step explanation:
$20/$0.10=200
Answer:
15.0
Step-by-step explanation:
Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.
The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)