Answer:
<u>A. p(hat) = .139</u>
We divide our sample population by the amount who tested positive. 14851/107109 = .139.
<u>B. 1.62 million</u>
We just multiply the p times the population. 11.69 M * .139 = 1.62 M
<u>C. No</u>
It depends upon the sample method. From what I can tell, I assume all conditions are met and it was not biased.
If it wasn't random, that is a problem, but we aren't given this information.
We can test if it's small enough. It can't be larger than 10% of the population. 107109 * 10 < 11.69 million, so it's small enough.
We can also test if it's large enough. np and nq must be greater than 10. 107100 * .139 > 10, 107100 * .861 > 10.
Answer:
It cooled 58.4 degrees
Step-by-step explanation:
T(t) = 68 + 144e ^(-.052t)
We want to find the value when t= 10
T(10) = 68 + 144e ^(-.052*10)
= 68 +85.611
T(10) =153.611
We also need to know
T(0)= 68 + 144e ^(-.052*0)
=68+144
=212
We want to know how much it cools
That would be the temperature at time 0 minus the temperature at time 10
T(0) - T (10)
212-153.611
58.389
To the nearest tenth
58.4 degrees
Answer:
Brainliest!!!
Step-by-step explanation:
see picture
Answer:
x=-5/2, -3
Step-by-step explanation:
2x^2+11x+15=0
factor out the trinomial
(2x+5)(x+3)=0
zero property,
2x+5=0, x+3=0
2x=0-5=-5, x=-5/2
x=0-3=-3

Hey there! Our goal here is to isolate the variable on one side of the equation.
