Answer: 1.08(99.95x) + 5 total nights
Explanation:
The standard error of the difference of sample means is 0.444
From the complete question, we have the following parameters
<u>Canadians</u>
- Sample size = 50
- Mean = 4.6
- Standard deviation = 2.9
<u>Americans</u>
- Sample size = 60
- Mean = 5.2
- Standard deviation = 1.3
The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.
This is represented as:
![SE = \frac{\sigma}{\sqrt n}](https://tex.z-dn.net/?f=SE%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%20n%7D)
The standard error of the Canadian sample is:
![SE_1 = \frac{2.9}{\sqrt{50}}](https://tex.z-dn.net/?f=SE_1%20%3D%20%5Cfrac%7B2.9%7D%7B%5Csqrt%7B50%7D%7D)
So, we have:
![SE_1 = 0.41](https://tex.z-dn.net/?f=SE_1%20%3D%200.41)
The standard error of the American sample is:
![SE_2 = \frac{1.3}{\sqrt{60}}](https://tex.z-dn.net/?f=SE_2%20%3D%20%5Cfrac%7B1.3%7D%7B%5Csqrt%7B60%7D%7D)
So, we have:
![SE_2 = 0.17](https://tex.z-dn.net/?f=SE_2%20%3D%200.17)
The standard error of the difference of sample means is then calculated as:
![SE= \sqrt{SE_1^2 + SE_2^2}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7BSE_1%5E2%20%2B%20SE_2%5E2%7D)
This gives
![SE= \sqrt{0.41^2 + 0.17^2}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7B0.41%5E2%20%2B%200.17%5E2%7D)
![SE= \sqrt{0.197}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7B0.197%7D)
Take square roots
![SE= 0.444](https://tex.z-dn.net/?f=SE%3D%200.444)
Hence, the standard error of the difference of sample means is 0.444
Read more about standard errors at:
brainly.com/question/6851971
Personally I think it’s easiest to read over just the definitions over and over and then go back to the words and say oh yeah that’s this definition also make sure u don’t memorize them in order IT WONT BE THAT WAY ON THE TEST anddd quizlet is ur bff bc they usually have any or most sets or vocab
What does this mean? Assuming you're talking about listening to the song on a computer, you'd be using a software.