3 years ago

Solve using the given matrices

Mathematics

1 answer:

Zina [86]3 years ago

8 0

Answer:

C11=1*1-1*3=1-3=-2

C12=1*2-1*4=2-4=-2

C21=2*1+1*3=2+3=5

C22=2*2+1*4=4+4=8

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Answer:

$\displaystyle A=\frac{3h^2}{2}+h$

Step-by-step explanation:

<u>Area of trapezoid</u>

Given a trapezoid shape whose parallel sides measure b1 and b2 and whose height (perpendicular to the base) is h, then the area of the trapezoid is given by

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and height h

Thus

$\displaystyle A=\frac{2h+1+h+1}{2}\cdot h=\frac{3h+2}{2}\cdot h$

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Answer: - 2 and 6

Step-by-step explanation:

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hichkok12 [17]

3. (t^2) - 4
4. (1/5)*s + 4

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What is the solution to this system of equations?<br> x = 12 − y<br> 2x + 3y = 29

Elenna [48]

Let’s arrange the fist equation
x+y=12
2x+3y=29

Multiply equation 1 by 2
So it will be

2x+2y=24

Subtract eq 1 from eq 2

2x+3y=29
2x+2y=24
—————-
Y =5

Put value of y in eq 1

2x+2y=24
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Answer:

Step-by-step explanation:

The x intercept is when y = 0

x + 3(0) = 6

x = 6

So (6,0) and m = 6

the y intercept is when x = 0

0 + 3y = 6 Divide by 3

y = 6/3

y = 2

the y intercept is (0,2) and n = 2

Answer

m + n = 6 + 2 = 8

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