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Katarina [22]
3 years ago
11

Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation

ship between Meg's age (m) and Victor's age (v):
m = v + 6
m = 5v − 2

Which is a possible correct method to find Meg's and Victor's ages?
Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Since no possible correct method is posted, I will suggest a couple.

Method 1: guess and check

Works well for simple problems involving integers like this one.

Victor's age must be zero or greater than one, say one.

Guess v=1, find m=v+6=7, check m=5v-2=5-2=3 no good.

we need to make v bigger

Guess v=2, find m=v+6=2+6=8, check m=5v-2=5*2-2=8 ✔

So v=2, m=8.

Method 2:

Solve the system of two equations.

since the left-hand sides is m in both equations, and since m=m, we just have to equate the right-hand sides to solve for v.

5v-2=v+6

Solve for v

5v-v = 6+2

4v=8

v=2,

so again, v=2, m=v+6=2+6=8.

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timurjin [86]
The multiply choice were worth 4 points. 
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So basically you can enter any number. At first I picked 3 and then I did the math and I got 73 points for Gretchen and 76 points for Ezia. 

Then I pick four and then I got 91 points for them both. This is how I got the answer: 

18x+19=15x+31
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5 0
3 years ago
Read 2 more answers
2. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i and 2-2i.
inna [77]

The polynomial equation for the given roots is x³-7x²+20x-24=0.

Given that, the polynomial equation of the smallest degree whose roots are 3, 2+2i and 2-2i.

Now, we need to write the polynomial equation.

<h3>What is a polynomial equation? </h3>

A polynomial equation is an equation where a polynomial is set equal to zero. i.e., it is an equation formed with variables, non-negative integer exponents, and coefficients together with operations and an equal sign. It has different exponents. The highest one gives the degree of the equation. For an equation to be a polynomial equation, the variable in it should have only non-negative integer exponents. i.e., the exponents of variables should be only non-negative and they should neither be negative nor be fractions.

Now, x=3, x=2+2i and x=2-2i

x-3, x-2-2i and x-2+2i

So, the polynomial equation is (x-3)(x-2-2i)(x-2+2i)=0

⇒(x-3)(x(x-2-2i)-2(x-2-2i)+2i(x-2-2i))=0

⇒(x-3)(x²-2x-2xi-2x+4+4i+2xi-4i-4i²)=0

⇒(x-3)(x²-2x-2x+4-4i²)=0

⇒(x-3)(x²-4x+4+4)=0 (∵i²=-1)

⇒(x-3)(x²-4x+8)=0

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⇒x³-4x²+8x-3x²+12x-24=0

⇒x³-7x²+20x-24=0

Therefore, the polynomial equation for the given roots is x³-7x²+20x-24=0.

To learn more about the polynomial equation visit:

brainly.com/question/20630027.

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3 0
1 year ago
I need help x-x please
KengaRu [80]


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6 0
3 years ago
What is the Compound Inequality that is true for the missing side length? 3cm, 4cm, Xcm
Brrunno [24]

Answer:

x< 3+4\: and\\\left | 3-4 \right |

Step-by-step explanation:

1. Well, when it comes to triangles. Mainly Pythagorean Triple, right triangles whose sides are 3,4,5 or  5,11,12

2. Keeping in mind this a Pythagorean Triple, then x=5

3. Then we can write it as Compound Inequality by combining the Statements for an Inequality of Triangle:

We can write it as

5

Or we can do:

4

and:

3

4. Writing in terms of x:

x

3 0
3 years ago
Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, ver
Artemon [7]
Check the picture attached.

Let OB be the radius of circle with center O.

Let B' be the image of B after the described rotation

OB and OB' are sides of the equilateral triangle OBB'.

The x coordinate of B' is the midpoint of OB, that is 5.

In the right triangle B', point (5, 0) and B:

Distance point (5, 0) to B is 5
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so by the pythagorean theorem:

a= \sqrt{ 10^{2} - 5^{2} } = \sqrt{ 2^{2} *5^{2} - 5^{2} }= \sqrt{5^{2}(4-1)}=5 \sqrt{3} units



Answer: 5 \sqrt{3}

3 0
3 years ago
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