Find the distance between the points (-4, -3) and (4, 3).

Need math help!! answer choices are 80 , 40, 20, and 60

vivado [14]

Answer:

60

Step-by-step explanation:

The corresponding angles of the triangles are given, y + 10 and 2y - 40. You need to first find the value of the variable (in this case, y), and to do this, you need to set them equal to one another:

y + 10 = 2y - 40

Subtract y from both sides:

y + 10 = 2y - 40

-y -y

____________

10 = y - 40

Add 40 to both sides:

10 = y - 40

+40 +40

________

50 = y

Now that we have the value of y, you need to plug the value into one of the expressions (either one will come out with the same answer):

y + 10

50 + 10 = 60

OR

2y - 40

2(50) - 40

100 - 40 = 60

5 0

3 years ago

3\sqrt{2} - 2\sqrt{18} + 6\sqrt{8}[/tex]

Stella [2.4K]

Answer:

$\sf \bold 9\sqrt{2}$

Step-by-step explanation:

<h3>Simplifying radicals</h3>

Step1: Prime fatorize and reduce to simplest form

Step2: Combine like radicals

$\sf 3\sqrt{2} - 2\sqrt{18}+6\sqrt{8}= 3\sqrt{2}- 2\sqrt{3*3*2}+6\sqrt{2*2*2}$

$\sf = 3\sqrt{2}-2*3\sqrt{2} +6*2\sqrt{2}\\\\=3\sqrt{2}-6\sqrt{2}+12\sqrt{2}\\\\=(3-6+12)\sqrt{2}\\\\ = 9\sqrt{2}$

5 0

2 years ago

Brock is a plumber. He charges a flat rate of $40 to visit a house to inspect it's plumbing. He charges an additional $20 for ev

Rina8888 [55]

where are the graphs?

3 0

3 years ago

Read 2 more answers

Find the point P on the graph of the function y=√x closest to the point (9,0)

Sphinxa [80]

Answer:

$\displaystyle \frac{17}{2}$ .

Step-by-step explanation:

Let the $x$ -coordinate of $P$ be $t$ . For $P\!$ to be on the graph of the function $y = \sqrt{x}$ , the $y$ -coordinate of $\! P$ would need to be $\sqrt{t}$ . Therefore, the coordinate of $P \!$ would be $\left(t,\, \sqrt{t}\right)$ .

The Euclidean Distance between $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ is:

$\begin{aligned} & d\left(\left(t,\, \sqrt{t}\right),\, (9,\, 0)\right) \\ &= \sqrt{(t - 9)^2 +\left(\sqrt{t}\right)^{2}} \\ &= \sqrt{t^2 - 18\, t + 81 + t} \\ &= \sqrt{t^2 - 17 \, t + 81}\end{aligned}$ .

The goal is to find the a $t$ that minimizes this distance. However, $\sqrt{t^2 - 17 \, t + 81}$ is non-negative for all real $t\!$ . Hence, the $\! t$ that minimizes the square of this expression, $\left(t^2 - 17 \, t + 81\right)$ , would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ .

Differentiate $\left(t^2 - 17 \, t + 81\right)$ with respect to $t$ :

$\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17$ .

$\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2$ .

Set the first derivative, $(2\, t - 17)$ , to $0$ and solve for $t$ :

$2\, t - 17 = 0$ .

$\displaystyle t = \frac{17}{2}$ .

Notice that the second derivative is greater than $0$ for this $t$ . Hence, $\displaystyle t = \frac{17}{2}$ would indeed minimize $\left(t^2 - 17 \, t + 81\right)$ . This $t\!$ value would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ , the distance between $P$ $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ .

Therefore, the point $P$ would be closest to $(9,\, 0)$ when the $x$ -coordinate of $P\!$ is $\displaystyle \frac{17}{2}$ .

8 0

3 years ago

What number does x stand for in this equation? -7x + 6=27

AURORKA [14]

⓵ You need to solve the left side first in order to isolate the × and find it’s value :

-7× + 6 = 27
-6 -6
↓

-7× = 21
÷-7 ÷-7

↓

× = -3

If you find it too difficult to divide a number by a negative, just divide 21 by 7 and always remember that when dividing, when the signs are different the answer is negative. So knowing that you could just divide 21 by 7, which is 3, and add a negative sign in front!

I hope this helped, if there’s anything let me know! ☻

3 0

4 years ago