Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
20mn - 30m
As you can see, both numbers are divisible by 10m. So if you were to divide them both, you would be left with, 10m (2n - 3), which would be the correct answer.
Answer:
3a^4
Step-by-step explanation:
Hope this helps!
Cevap:
3700 ABD doları
Adım adım açıklama:
Haftalık satış = 100.000 $
Haftalık satışlarda kazanılan yüzde =% 2,5 = (0,025 * 100.000 ABD Doları) = 2500 ABD Doları
Saatlik kazanç = 30 $
Çalışılan saat sayısı = 40 saat
Çalışılan saat için kazanç = 40 * 30 $ = 1200 $
Toplam kazanç:
Haftalık satış yüzdesi + çalışılan saat için kazanç
(1200 ABD doları + 2500 ABD doları) = 3700 ABD doları
Answer:
the correct answer is (-1, 2)
Step-by-step explanation:
