Using the percentage concept, it is found that 75% of the population of Gorgeous Sunset is on Beautiful Sunrise now.
<h3>What is a percentage?</h3>
The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

In this problem, we have that:
- We consider that the population of both Beautiful Sunrise and Gorgeous Sunset islands is of x.
- There is a fiesta at Beautiful Sunrise, and a number a of people from Gorgeous Sunset are coming, hence, there will be x + a people at Beautiful Sunrise and x - a people t Gorgeous Sunset.
The percentage of people from Gorgeous Sunset is on Beautiful Sunrise now is:

Now the number of people on Beautiful Sunrise is seven times the number of people on Gorgeous Sunset, hence:

We can find a <u>as a function of x</u> to find the percentage:





Then, the percentage is:




75% of the population of Gorgeous Sunset is on Beautiful Sunrise now.
You can learn more about the percentage concept at brainly.com/question/10491646
Answer:C 5000 feet
Step-by-step explanation:It’s slightly less then a mile.
Answer:
13/7
7 goes into 13 1 time
13 minus 7 equals 6
Answer 1 6/7
Step-by-step explanation:
Answer:
sin²x
Step-by-step explanation:
we have
(1 − cos x)(1 + cos x)=1-cos²x
Remember that
sin²x+cos²x=1 ------> i-cos²x=sin²x
therefore
(1 − cos x)(1 + cos x)=sin²x
9514 1404 393
Answer:
(c) 14.5 cm
Step-by-step explanation:
The relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(65°) = BC/BA
BC = BA·sin(65°) ≈ (16 cm)·0.9063 ≈ 14.501 cm
BC ≈ 14.5 cm
_____
<em>Additional comment</em>
As is often the case, a simple estimate is all that is needed to identify the correct answer choice.
You only need to know how the long side of a right triangle compares to the others. In an isosceles right triangle, both legs are √2/2 ≈ 0.71 times the hypotenuse. The long side of a right triangle will never be shorter than that. This means the long side must be greater than about 11.2, and cannot be greater than 16. There is only one answer choice in that range.