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adelina 88 [10]
3 years ago
5

What is the molarity of a solution with 2.1 mol of HCl in 400 mL of water? (M = mol/L)

Chemistry
1 answer:
natka813 [3]3 years ago
6 0

Answer:

A

Explanation:

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What are the two main types of energy?
Harlamova29_29 [7]
Kinetic and potential energy, are the two main types of energy! Hope this helps:)
3 0
3 years ago
Read 2 more answers
The volume of a sample of hydrogen gas was decreased from 14.65 L to 7.94 L at constant temperature. If the final pressure exert
adoni [48]

Answer:

The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.

Explanation:

Using Boyle's law

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 14.65 L

V₂ = 7.94 L

P₁ = ?

P₂ = 5.02 atm

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{P_1}\times {14.65}={5.02}\times {7.94}\ atm

{P_1}=\frac {{5.02}\times {7.94}}{14.65}\ atm

{P_1}=2.7207\ atm

<u>The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.</u>

8 0
3 years ago
A student was holding a metal rod to a candle flame. After a while he noticed that his hand was getting hot.
ArbitrLikvidat [17]

Answer:

Conduction

Explanation:

Conduction is when energy directly travels through a solid to get from one point to another.

4 0
3 years ago
Which of the following is not a benefit of using a scientific model?
schepotkina [342]

Answer:

Benifits of scientific modeling

Explanation:

When students are engaged in scientific modeling, they are able to notice patterns and develop and revise representations that become useful models to predict and explain--making their own scientific knowledge stronger, helping them to think critically, and helping them know more about the nature of science.

5 0
3 years ago
What is the mass in grams of 250 ml of PH3 at STP?
SIZIF [17.4K]
We can find the number of moles of PH₃ using ideal gas law equation
PV = nRTwhere 
P - standard pressure - 101 325 Pa
V - volume - 250 x 10⁻⁶ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 273 K
substituting the values in the equation 
101 325 Pa x 250 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 273 K
n = 0.011 mol
therefore mass of PH₃ = 0.011 mol x 34 g/mol = 0.374 g
mass of PH₃ is 0.374 g
8 0
4 years ago
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