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3 years ago

Which condition In a nebula would prevent nuclear fusion

Chemistry

2 answers:

german3 years ago

7 0

Answer:

Decreasing the overall volume of the gases in a nebula would prevent nuclear fusion.

Explanation:

A nebula refers to a huge cloud of gas and dust in space. Some nebulae arise from the gas and dust withdrawn due to the explosion of a dying star like a supernova. Other nebulae are the locations where the novel stars are starting to get produce. Due to this, some nebulae are also known as star nurseries. The reduction in the entire volume of gases mainly hydrogen could inhibit the nuclear fusion in the nebula.

NemiM [27]3 years ago

5 0

A decrease in the overall volume of gases namely hydrogen would prevent nuclear fusion in a nebula.

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Assuming the relative rate of secondary hydrogen atom abstraction for the chlorination of propane is 3.9 times faster than the r

Ghella [55]

Answer:

% of n-propyl chloride = 43.48 %

Explanation:

There are 2 secondary hydrogens and 6 primary hydrogens

The rate of abstraction of seondary hydrogen = 3.9 X rate of abstraction of primary hydrogen

probability of formation of isopropyl chloride = 3.9 X 1 (relative rate X relative number of secondary hydrogens)

Probability of formation of n-propyl chloride = 1 X 3 (relative rate X relative number of primary hydrogens)

Total probability = 3.9

% of n-propyl chloride = 3 X 100 / 6.9 = 43.48 %

7 0

4 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

4 years ago

Besides water, what is the product of a Neutalization Reaction between H2SO4 and LiOH?

tigry1 [53]

Answer:

The answer to your question is d. Li₂SO₄

Explanation:

Data

H₂SO₄ reacts with LiOH

Process

This is a neutralization reaction that occurs between an acid and a base and the products will always be water and a binary or ternary salt.

In this reaction, the acid is H₂SO₄ and the base is LiOH, then the products will be water and Lithium sulfate.

Balanced chemical reaction

H₂SO₄ + LiOH ⇒ Li₂SO₄ + H₂O

8 0

3 years ago

Read 2 more answers

Consider the system at equilibrium. 2 H 2 ( g ) + S 2 ( g ) − ⇀ ↽ − 2 H 2 S ( g ) How will increasing the concentration of S 2 s

borishaifa [10]

Answer:

1) the balance will shift to the right

2) the balance will shift to the left

3) There will be no effect on the position of the equilibrium.

Explanation:

Step 1: Data given

The Principle of Le Chatelier says 'If the concentration of one of the reaction partners changes, the balance will shift to counteract that concentration change.

Step 2: The balanced equation

2H2(g) + S2(g) ⇆ 2H2S(g)

Step 3: How will increasing the concentration of S2 shift the equilibrium?

If the S2 concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the right, and so the H2S concentration will increase.

Step 4: How will increasing the concentration of H2S shift the equilibrium?

If the H2S concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the left, and so the H2 and S2 concentration will increase.

Step 5: How will adding a catalyst shift the equilibrium?

Reactions can be sped up by the addition of a catalyst.

In the presence of a catalyst, both the forward and reverse reaction rates will speed up equally, thereby allowing the system to reach equilibrium faster.

Adding a catalyst makes absolutely no difference to the position of equilibrium.

6 0

4 years ago

What does group 16 (oxygen family) have in common

Dimas [21]

Answer: here is your answer

Explanation:

The oxygen family consists of the elements that make up group 16 on the periodic table: oxygen, sulfur, selenium, tellurium, and polonium. These elements all have six electrons in their outermost energy level, accounting for some common chemical properties among them.

7 0

3 years ago

Read 2 more answers