Question

1) sqrt x^+6x+9 if x≥3

Answer 1

Answer:

Step-by-step explanation:

first one:

$x^{2}+6x+9={(x+3)}^{2} \\\sqrt{{(x+3)}^{2} }=x+3$

second one:

$x^{2}+6x+9=(x+3)^{2} \\\sqrt{(x+3)^{2} } = x+3$

third one:

$x^{2} -6x+9=(x-3)^{2} \\\sqrt{(x-3)^{2} } =|x-3| \ \ (because \ x$