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MArishka [77]
3 years ago
14

32.443 rounded to the nearest hundredth

Mathematics
2 answers:
Naddik [55]3 years ago
5 0
The answer would be 32.44 because the 3 is smaller than 5, therefore closer to 40 than 50.
Roman55 [17]3 years ago
5 0

The digit place to the right of the hundredths digit is the thousandths place. The digit in that place is less than 5, so that digit and all to its right can be dropped. Your rounded number is

... 32.44

_____

Had the thousanths place digit been 5 or greater, you would have increased the hundredths-place digit by 1 before dropping digits to its right.

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If a diameter is 12.5 cm, what is the radius?
Jlenok [28]

Answer:

6.25

Step-by-step explanation:

8 0
2 years ago
What is the slope of the line that passes through the points (3, 4) and (5, –4)?
balandron [24]
M = -4 -4 / 5- 3 = -8/2 = -4

y = -4x + b

4 = -12 + b

b = 16

y = -4x + 16
3 0
3 years ago
Use rounding to estimate the difference of 18.14 - 9.88.<br><br> A. 6<br> B. 9<br> C. 7<br> D. 8
Anna35 [415]

Answer:


D. 8 is the answer


7 0
2 years ago
Read 2 more answers
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
Please help me with this geometry question. x and pr needed ao basically like this x=(answer), PR=(answer). Thank you
Dennis_Churaev [7]

Answer:

x = -1, PR = 38.

Step-by-step explanation:

As Q is the midpoint of PR

PQ = QR

6x + 25 = 16 - 3x

9x = -9

x = -1.

PR

= 6x + 25 + 16 - 3x

= 6(-1) + 25 + 16 - 3(-1)

= -6 + 25 + 16 + 3

= 38.

7 0
2 years ago
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