Answer:
Y' = 360ex+ 30e
Step-by-step explanation:
Y=e×6x×(6x+1) × 5
y'= d/dx (e×6x ×(6x+1)×5)
y'=d/dx(30ex ×(6x+1))
y'=d/dx(180ex^2 + 30ex)
y'=d/dx(180ex^2) + d/dx (30ex)
Calculate the derivative
y'=180e×2x +30e
y'=360ex+30e
Answer:
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Step-by-step explanation:
Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by:
c^2=a^2+b^2
where:
c is the hypotenuse
a and b are the legs.
c=10
a=6
b=(x-6)
thus plugging the values in the equation and solving for x we get:
10^2=6^2+(x-6)^2
100=36+x^2-12x+36
100=x^2-12x+72
0=x^2-12x-28
factoring the above we get:
0=(x+2)(x-14)
hence
x=-2 or x=14
given that there is no negative distance then
x=14
thus the value of x is 14
