Multiplying Binomials<br> Pls Help

iVinArrow [24]

For 1 multiply both sides by 3 which gives you 3y-y=12. Then combine like terms 2y=12. Lastly divide both sides by 2 and you get y=6. And for 3 first multiply both sides by 4 which gives you 6y-32=y+8. After that combine like terms 6y-y-32=8. Now add the equation together 5y=40 and then divide by 5 and get y=8

5 0

4 years ago

Can someone help with this question below?

Oxana [17]

Answer:

C = 106.76 cm

Step-by-step explanation:

In the diagram, we are given the diameter (d), which is 34 cm. Using the formula you are given, we know circumference is 3.14 × d

C = 3.14 × d

C = 3.14 × (34)

C = 106.76 cm

The circumference is around 106.76 cm

6 0

3 years ago

Read 2 more answers

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago

Help plzzzzzzzzzzz WILL MARK BRAINLIST

Ivanshal [37]

Answer:

7

Step-by-step explanation:

(-1^2)x 3 = 3

-1 x 4 = -4

3--4 = 7

3 0

3 years ago

Read 2 more answers

Y=x+2 2x-y=-4 Solve the systems of equations

larisa86 [58]

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)

4 0

4 years ago

Read 2 more answers

Multiplying Binomials Pls Help