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Rina8888 [55]
3 years ago
5

Last school year, the student body of a local university consisted of 30% freshmen, 24% sophomores, 26% juniors, and 20% seniors

. A sample of 300 students taken from this year's student body showed the following number of students in each classification.
Freshmen 83
Sophomores 68
Juniors 85
Seniors 64
We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year.

Mathematics
1 answer:
Natalija [7]3 years ago
6 0

Answer:

There has been no change in the classifications between the last school year and this school year.

Step-by-step explanation:

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

<em>H</em>₀: The observed frequencies are same as the expected frequencies.

<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

\chi^{2}=\sum\limits^{n}_{i=1}\frac{(O_{i}-E_{i})^{2}}{E_{i}}

The expected values are computed using the formula:

E_{i}=p_{i}\times N

Here, <em>N</em> = 300

Use Excel to compute the values.

The test statistic value is:

\chi^{2}=\sum\limits^{n}_{i=1}\frac{(O_{i}-E_{i})^{2}}{E_{i}}=1.662

The test statistic value is, 1.662.

The degrees of freedom of the test is:

<em>n</em> - 1 = 4 - 1 = 3

The significance level is, <em>α</em> = 0.05.

Compute the p-value of the test as follows:

<em>p</em>-value = 0.6454

*Use a Chi-square table.

p-value = 0.6454 > <em>α</em> = 0.05.

So, the null hypothesis will not be rejected at 5% significance level.

Thus, concluding that there has been no change in the classifications between the last school year and this school year.

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In a jar of 250 jelly beans, a random sample of 25 is pulled. In the random sample, 15 of the jelly beans are red. How many jell
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Classify the equation, 7x+6=7x-5, as having one solution, no solution, or infinitely many solutions.
Ksenya-84 [330]

Answer:

Step-by-step explanation:

7x + 6 = 7x - 5

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5 0
3 years ago
There is a total of 2,512 people attending the fun fair. 5/8 of sttemdees are students and 1/4 of attendees are parents. the res
kvv77 [185]

Answer:

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of people attending the fun fair = 2,512

Fraction of people attending the fun fair that are students = 5/8

Fraction of people attending the fun fair that are parents = 1/4

Rest of the people attending the fun fair lives in the neighborhood

2. Let's calculate the number of students, parents and people living in the neighborhood

Students:

Fraction of people attending the fun fair that are students = 5/8

5/8 * 2,512 = 1,570

1,570 of the people attending the fun fair are students

Parents:

Fraction of people attending the fun fair that are parents = 1/4

1/4 * 2,512 = 628

628 of the people attending the fun fair are parents

People living in the neighborhood

2,512 - 1,570 - 628 = 314

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

8 0
3 years ago
WILL MARK YOU BRAINLIEST!!!!!!
My name is Ann [436]

Answer:

y = 88

Step-by-step explanation:

Don't worry about the other stuff, just worry about what's in the triangle that has Y.

53°, 39°, and y°

the sum should be equal to 180 so add 53 adn 39 and subtract it from 180.

180 - (53 + 39) = y

180 - 92 = y

88 = y

Hope this helped! Pls Brainliest my answer! It would help amd mean a lot! ;)

6 0
3 years ago
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