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2 years ago

What is the sum of the 9th square number and the 3rd cube number?

Mathematics

2 answers:

Lesechka [4]2 years ago

7 0

The sum of the 9th square number and 3rd cube number is 108

Fiesta28 [93]2 years ago

6 0

Answer:

9×9=81

3×3×3=27

27+81=108

108 is the answer

You might be interested in

Insert 2 sets of parentheses to make each sentence true: 2 x 14 – 9 – 17 – 14 = 7

Morgarella [4.7K]

Answer:

- 12

Step-by-step explanation:

2x14= 28

28-9=19

19-17=2

2- -14= - 12

3 0

3 years ago

PLEASE ANSWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!

stealth61 [152]

Answer:

32 units²

Step-by-step explanation:

this shape is a trapezoid with a height of 4 and bases that are 4 and 12 units in length

formula is: 1/2(height) x (sum of bases)

A = 1/2(4)(4 + 12)

A = 2(16)

A = 32

7 0

2 years ago

Read 2 more answers

Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46

JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

$M = \frac{50463-38737}{2} = 5863$

Relating the margin of error with the sample size:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.64.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

For this problem, we have that $\sigma = 14300, M = 5863$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$5863 = 1.645\frac{14300}{\sqrt{n}}$

$5863\sqrt{n} = 1.645*14300$

$\sqrt{n} = \frac{1.645*14300}{5863}$

$(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2$

$n = 16$

The sample size was of 16.

7 0

2 years ago

A student earned a grade of 80% on a math test that had20 problems. How many problems on this test did the student answer correc

Georgia [21]

Answer:

Only 16 problems correct

Step-by-step explanation:

Well I thought that since 80% is 4/5 then I should do 20 divided by 5 which will get me 4 and since I'm doing 4/5 I should go all the way up to 80% of 20 which will get me 16.

I'm not making that much sense but

Hope this helps :)

5 0

2 years ago

Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec

vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

$\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}$

Hence, we have:

$\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\ \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}$

Divide the expression for the fifth term by the expression for the second term:

$\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}$

Substituting the value of r into any of the expression:

$\begin{gathered} ar\text{ = 18} \\ a\text{ }\times\text{ 2 = 18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}$

Hence, the explicit rule for the sequence is:

$a_n\text{ = 9\lparen2\rparen}^{n-1}$

5 0

1 year ago