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3 years ago

What is the square root of 28

Mathematics

2 answers:

Oduvanchick [21]3 years ago

6 0

The decimal form would be 5.29150262

natima [27]3 years ago

6 0

That square root of 28

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What is the answer...?

Finger [1]

Answer:The answer is c

Step-by-step explanation:

Multiply both side is the equation by -1.

Sum the equations vertically to eliminate at least one variable

Divide both sides of the equation by 3

Substitute the given value of y into the equation 2x+3y=8

and then solve for x

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3 years ago

How many different ways can 9 people line up for a picture?

AleksandrR [38]

Answer:

262880

i had a test with the same question, i promise its right :)

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4 years ago

Can y’all help me???

Andreyy89

You will need 3 cups :)

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3 years ago

Solve the following equation with the initial conditions. x¨ + 4 ˙x + 53x = 15 , x(0) = 8, x˙ = −19

Katen [24]

$x''+4x'+53x=15$

has characteristic equation

$r^2+4r+53=0$

with roots at $r=-2\pm7i$ . Then the characteristic solution is

$x_c=C_1e^{(-2+7i)t}+C_2e^{(-2-7i)t}=e^{-2t}\left(C_1\cos(7t)+C_2\sin(7t)\right)$

For the particular solution, consider the ansatz $x_p=a_0$ , whose first and second derivatives vanish. Substitute $x_p$ and its derivatives into the equation:

$53a_0=15\implies a_0=\dfrac{15}{53}$

Then the general solution to the equation is

$x=e^{-2t}\left(C_1\cos(7t)+C_2\sin(7t)\right)+\dfrac{15}{53}$

With $x(0)=8$ , we have

$8=C_1+\dfrac{15}{53}\implies C_1=\dfrac{409}{53}$

and with $x'(0)=-19$ ,

$-19=-2C_1+7C_2\implies C_2=-\dfrac{27}{53}$

Then the particular solution to the equation is

$\boxed{x(t)=\dfrac1{53}e^{-2t}(409cos(7t)-27\sin(7t)+15)}$

8 0

3 years ago

Discriminant and the number of real roots for this equation 9x2+12x+4=0

BaLLatris [955]

The discriminant is b^2-4ac
In this equation 9=a, 12=b, 4=c
Plugging into the formula
12^2-4(9)(4)=
144-324 =
-180 is the discriminant
Since the discriminant is a negative number there are no real roots

8 0

3 years ago