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Cerrena [4.2K]
3 years ago
10

Triangles ABC and DEF are similar. Find the length of side DF

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

side df is the same as side ac


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Mila [183]

Answer:

?

Step-by-step explanation:

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6 0
3 years ago
What is the vertex of the graph of f(x) = |x – 13| + 11?
dybincka [34]

Answer:

The vertex of the graph of f(x) = |x - 13| + 11 is (13, 11).

Step-by-step explanation:

There is something called absolute value in the given function. It means two equations will result from it.

When (x -13) > 0 the resultant equation is

y = f(x) = x - 13 + 11 = x - 2 - This will be the first equation

or  

When (x - 13) < 0 the resultant equation is

y = f(x) = -(x - 13) + 11 = -x + 24 - This will be the second equation.

The intersection of these lines will give the vertex as found by solving both equations at the same time.  

y = x - 2

y = -x + 24

_________

2y = 0 + 22

y =  \frac{22}{2} = 11

Replacing the value of y for any one;

x = 11 + 2 = 13 (first one)

x = 24 - 11 = 13 (second one)

The vertex is (13, 11)

8 0
2 years ago
Read 2 more answers
Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters
Mumz [18]

The various answers to the question are:

  • To answer 90% of calls instantly, the organization needs four extension lines.
  • The average number of extension lines that will be busy is Four
  • For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$

Generally, the equation for is  mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about extension lines

brainly.com/question/13362603

#SPJ1

8 0
2 years ago
Solve for x: 5x - 2 = 3x + 8
gayaneshka [121]

5x-2=3x+8


X=5

That's your answer
8 0
2 years ago
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How much space is inside the steps?
dexar [7]
.015 + .06= .075

not sure if this is correct i did my best
5 0
3 years ago
Read 2 more answers
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