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3 years ago

5/6 = 1/3+d and x/x is a fraction

1 answer:

7 0

$\dfrac{1}{3}+d=\dfrac{5}{6}\qquad|-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1\cdot2}{3\cdot2}\\\\d=\dfrac{5}{6}-\dfrac{2}{6}\\\\d=\dfrac{5-2}{6}\\\\d=\dfrac{3}{6}\\\\d=\dfrac{3:3}{6:3}\\\\\boxed{d=\dfrac{1}{2}}$

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Answer:

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3 years ago

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Step-by-step explanation:

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3 years ago

What is an equation of the line that passes through the points (0, -4) and (-4, 6)?

olganol [36]

Answer:

The equation of the line is.

$y=-\frac{5}{2}x-4$

Step-by-step explanation:

Given:

The given points are (0, -4) and (-4, 6)

The equation of the line passing through the points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is.

$\frac{x-x_{1}}{x_{2}-x_{1}}=\frac{y-y_{1}}{y_{2}-y_{1}}$

Thus, the equation of the line that passes through the points (0, -4) and (-4, 6) is

$\frac{x-0}{(-4)-0}=\frac{y-(-4)}{6-(-4)}$

$\frac{x}{-4}=\frac{y+4}{6+4}$

$-\frac{x}{4}=\frac{y+4}{10}$

$-\frac{10x}{4}=y+4$

$-10x=4(y+4)$

$-10x=4y+16$

$4y=-10x-16$

The above equation is divided by 2 both sides.

$2y=-5x-8$

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Therefore, the equation of the line that passes through the points (0, -4) and (-4, 6) is $y=-\frac{5}{2}x-4$

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3 years ago