Michelle exercises for half an hour everyday. How minutes in total does she exercise for over 5 hour?

From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri

Leviafan [203]

Answer:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=201.77$ represent the sample mean

$s=2.41$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =200$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :

Null hypothesis: $\mu = 200$

Alternative hypothesis: $\mu = 200$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

4 0

3 years ago

Someone help me please

tamaranim1 [39]

Answer:

$\sqrt{60}$

Step-by-step explanation:

Use the Pythagorean theorem a^2 + b^2 = c^2

In this case you are given a and c, so set the equation up like

2^2 + b^2 = 8^2

b^2 = 8^2 - 2^2

b = $\sqrt{8^{2} -2^{2} }$

b = $\sqrt{60}$

6 0

2 years ago

Use the Commutative Property and compatible numbers to calculate the sum. Explain how you used mental math. 23. 3 + 36. 7

erik [133]

May i ask is it 3+26 or is there more

3 0

4 years ago

Solve T=M(3+FG) for G.<br> G=?

xeze [42]

My answer was wrong, delete this answer or disregard

8 0

4 years ago

Fill in the missing values in the table for the quadratic function: f(x) = 1/3x^2+1

Vesnalui [34]

Answer:

[x] f(x)

[-6] 13

[-3] 4

[0] 1

[3] 4

[9] 28

Step-by-step explanation:

f(0) = (1/3)(0^2)+1 = 1

f(3) = (1/3)(3^2)+1 = 4

f(9) = (1/3)(9^2)+1 = 28

6 0

3 years ago