Question

The gas sample has a volume of 45.1 μL at 24.7 °C. What is the volume of the gas after the sample is heated to 37.2 °C at constant pressure?

Answer 1

Answer:

   V₂  = 46.99 μL.

Explanation:

Given that

V₁ = 45.1 μL

T₁ = 24.7°C  = 273 + 24.7 = 297.7 K

T₂ = 37.2°C = 273+37.2=310.2 K

Lets take  ,The final volume = V₂  

We know that ,the ideal gas equation  

If the pressure of the gas is constant ,then we can say that

$\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}$

${V_2}=V_1\times \dfrac{T_2}{T_1}$

Now by putting the values in the above equation we get

${V_2}=45.1\times \dfrac{310.2}{297.7}\ \mu \ L$

V₂  = 46.99 μL.

The final volume will be 46.99 μL.