Question

An object accelerates to a velocity of 34m/s over a time of 1.3 s the acceleration it experienced was 15 m/s squared what was the initial velocity

Answer 1

V=v0+at=>v0=v-at=34-15•1,3=34-19,5=14,5m/s

Answer 2

Answer:

Initial velocity, u = 14.5 m/s

Explanation:

It is given that,

Final velocity of the object, v = 34 m/s

Time, t = 1.3 s

Acceleration of the object, $a=15\ m/s^2$

To find,

Initial velocity of the object

Solution,

Let u is the initial velocity of the object. It can be calculated using the first equation of motion as :

$v=u+at$

$u=v-at$

$u=34-15\times 1.3$

u = 14.5 m/s

So, the initial velocity of the object is 14.5 m/s.