Mo: My number has two periods. One period has a 7 in the hundreds place. The other has an 8 in the tens place. Bo: My number als
2 answers:
Answer:
Mo:780
Bo:120
Step-by-step explanation:
We are given that
Mo:my number has two periods .One period has a 7 in the hundred place , other has an 8 in the tens place and other digits are zero.
Then the number of Mo's=
Bo: My number has two periods,one has a 1 in the hundred place ,other has a 2 in the tens place and other digits are zero.
Therefore, number of Bo's =
Hundred place of Mo's number is greater than the hundred place of Bo's number , therefore,Mo's number is greater than the Bo's number.
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Answer:
(x, y) = (-0.6, 0.8) or (1, 4)
Step-by-step explanation:
Use the second equation to substitute for y in the first.
(x -1)² +((2x +2) -2)² = 4
x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses
5x² -2x -3 = 0 . . . . . . . . . . subtract 4, collect terms
Now we can rearrange the middle term to ease factoring by grouping.
(5x² -5x) +(3x -3) = 0
5x(x -1) +3(x -1) = 0
(5x +3)(x -1) = 0
The values of x that make these factors zero are ...
x = -3/5, x = 1
The corresponding values of y are ...
y = 2(-3/5)+2 = 4/5 . . . . for x = -3/5
y = 2(1) +2 = 4 . . . . . . . . for x = 1
The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).
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A graphing calculator verifies these solutions.
