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Orlov [11]
3 years ago
8

Mo: My number has two periods. One period has a 7 in the hundreds place. The other has an 8 in the tens place. Bo: My number als

o has two periods. One has a 1 in the hundreds place. The other has a 2 in the tens place. Mo: All other digits in our numbers are zeros. So how can it be that your number is greater than my number? What are Mo’s and Bo’s numbers?
Mathematics
2 answers:
miv72 [106K]3 years ago
8 0
780 is mo's and bo's is 120
dexar [7]3 years ago
6 0

Answer:

Mo:780

Bo:120

Step-by-step explanation:

We are given that

Mo:my number has two periods .One period has a 7 in the hundred place , other has an 8 in the tens place and other digits are zero.

Then the number of Mo's=7\times 100+8\times 10+0=780

Bo: My number has two periods,one has a 1 in the hundred place ,other has a 2 in the tens place and other digits are zero.

Therefore, number of Bo's =1\times 100+2\times 10+0=120

Hundred place of Mo's number is greater than the hundred place of Bo's number , therefore,Mo's number is greater than the Bo's number.

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The sum of two numbers is 240. If one number is twice the other number, find the two numbers.
Deffense [45]

Answer:

The sum of two numbers is 240. The larger number is 6 less than twice the smaller. Find the numbers.

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Let the smaller be "x" ; Larger is "2x-6"

EQUATION:

x + 2x-6 = 240

3x= 246

x = 82 (smaller)

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Step-by-step explanation:

7 0
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If we try to simplify the ratio or try to multiply both by any number, we will get the equivalent ratio


Like :

\frac{4}{6}  \\


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Or multiply by any number,



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