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sukhopar [10]
3 years ago
14

What is the equation, in standard form, of a parabola that models the values in the table?

Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer:

Equation of parabola is: y=4x^{2} +3x-6

Step-by-step explanation:

By plotting a rough graph with the values given we get an opening upward parabola.

Standard equation for a parabola opening upwards is given by:

y=ax^{2}+bx+c

We can solve for a,b,c by substituting the given values of x and y.

Putting x=0 and y=-6 in the above equation,we get:

c = -6

Putting x=-2 and y=4, we get:

4a-2b=10  ---------1

Putting x=4 and y=70, we get:

16a+4b=76 --------2

Solving equation 1 and 2, we get

a=4 and b=3

Hence y=4x^{2} +3x-6

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Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr
NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Distance between B(0, 5) and C(4, 2):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(0, 5) = (x_1, y_1)

C(4, 2) = (x_2, y_2)

BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}

BC = \sqrt{(4)^2 + (-3)^2}

BC = \sqrt{16 + 9} = \sqrt{25}

BC = 5 units

Distance between C(4, 2) and D(1, -2)

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(4, 2) = (x_1, y_1)

D(1, -2) = (x_2, y_2)

CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}

CD = \sqrt{(-3)^2 + (-4)^2}

CD = \sqrt{9 + 16} = \sqrt{25}

CD = 5 units

Distance between E(-2, -2) and F(-5, 2):

EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

E(-2, -2) = (x_1, y_1)

F(-5, 2) = (x_2, y_2)

EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}

EF = \sqrt{(-3)^2 + (4)^2}

EF = \sqrt{9 + 16} = \sqrt{25}

EF = 5 units

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0
3 years ago
Using side lengths only, could the triangles be similar?
o-na [289]

Answer:

the answer is no

Step-by-step explanation:

8 0
3 years ago
Which property was used to simplify the expression?<br><br> (y^5)^2 = y^10
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<span>(y^5)^2 = y^10

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