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Kruka [31]
3 years ago
10

7 - 5x = -5x - 6x + 7

Mathematics
1 answer:
castortr0y [4]3 years ago
8 0

Answer: X=0

Step-by-step explanation:

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8th grade math please help! 8-10 points
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The third one, this is because you take your y2 and y1 values (y2=0 and y1=9 because these are the two y values given to you from each coordinate) and subtract 0-9. then you do the same, but with the x2 and x1 values. so your x1 value is 3 and your x2 value is 0, so you subtract 0 from 3. divide your second answer from the first answer, to get a gradient of -1/3 x. now using the first coordinate (0,9) you know that the y coordinate is 9. as the x value =0, we know that the line is passing through the y axis at 9 so 9 is your y intercept. this gives you the equation -1/3x+9. hope this helped and wasn't too confusing!
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3 years ago
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Solve for t. 2(t – 7) = 10
blagie [28]
<span>2(t – 7) = 10
2t - 14 = 10 ...expand by using distributive property
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I need this assignment done will give brainliest and extra points.
Travka [436]

Answer:

1a.2.5x³-2.25x²+3.5x-1.5

1b.No, they aren't equal. (worked out the product for both and they weren't equal, see below)

2a.-2x⁶+7x⁴+3x³-3x²+11x+20

2b.Yes. When multiplying, it doesn't matter which term/expression you put first

3. The equation has two solutions: x=-2, x=3

Step-by-step explanation:

1. (a)

(0.5x-0.25)(5x²-2x+6)

0.5x(5x²-2x+6)-0.25(5x²-2x+6)

2.5x³-x²+3x -1.25x²+0.5x-1.5

2.5x³-2.25x²+3.5x-1.5

(b)

(0.25x-0.5)(5x²-2x+6)

0.25x(5x²-2x+6)-0.5(5x²-2x+6)

1.25x³-0.5x²+1.5x -2.5x²+x-3

1.25x³-3x²+2.5x-3

This is not equal to our answer for 1(a), so we can see they're not the same.

2(a)

(-2x³+x-5)(x³-3x-4)

-2x³(x³-3x-4) +x(x³-3x-4) -5(x³-3x-4)

-2x⁶+6x⁴+8x³ +x⁴-3x²-4x -5x³+15x+20

-2x⁶+7x⁴+3x³-3x²+11x+20

(b)

Yes. When multiplying, it doesn't matter which term/expression you put first: xy=yx. For example, 2(3)=6 and 3(2)=6.

3

2x²-2x-12=0

(divide each term by 2)

x²-x-6=0

(x+2)(x-3)=0

Anything multiplies by zero is zero, so either x+2=0 or x-3=0

If x+2=0, x=-2. If x-3=0, x=3.

The equation has two solutions: x=-2, x=3

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