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mars1129 [50]
3 years ago
12

A combination lock has 5 different numbers. If each number can only be used ONCE, how many different combinations are possible?

Mathematics
1 answer:
Fantom [35]3 years ago
5 0
Hello,

The first digit may be 0,1,2..,9 thus 10 possibilities
The second digit may be 0,1,2,3...,9 but not equal to the first thus 9 possibilities
The 3th digit may be 0,1,2..,9 but not the first and not the 2th =>8 possibiliteis
...
In  Total, 10*9*8*7*6 combinations.
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7 0
3 years ago
Read 2 more answers
If f(x)=x2+1, then (f∘f)(x)=
PSYCHO15rus [73]

The resulting composite function (f∘f)(x) is x⁴+2x²+2

When a function is written inside another function, it is known as a composite function

Given the function f(x)=x²+1,

(f∘f)(x) = f(f(x))

f(f(x)) = f(x²+1)

This means we will need to replace x with x²+1 in f(x) as shown:

f(x²+1) = (x²+1)²+1

Expand

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Hence the resulting composite function (f∘f)(x) is x⁴+2x²+2

Learn more here: brainly.com/question/3256461

3 0
3 years ago
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