Answer:
Please find the expected genotypes and phenotypes of the progenies of each cross below.
Explanation:
In the MN blood-group locus of the gene, alleles LM and LN exhibit codominance i.e one allele is not dominant or recessive to the other, hence, they are both expressed when they occur in a heterozygous state (MN).
Considering the following crosses (find the punnet square attached);
a)LMLM x LMLN - The progeny are LMLM and LMLN in the genotypic ratio 1:1. Phenotypic ratio is Blood type M (1) : blood type MN (1)
b) LNLN x LNLN - The progeny are all LNLN offsprings with a phenotypic and genotypic ratio 4:0. All offsprings will have a blood type N (4)
c) LMLN x LMLN - The progenies are LMLM, LMLN and LNLN in the genotypic ratio 1:2:1 respectively. The phenotypic ratio is Blood type M (1) : L
Blood type MN (2) : Blood type N (1)
d) LMLN x LNLN - The progeny are LMLN and LNLN with genotypic ratio 1:1 and phenotypic ratio blood type MN (1) : blood type N (1)
e) LMLM x LNLN - The progeny are all LMLN offsprings with penotypic ratio blood type MN (4)
The right answer is DNA is located in the nucleus.
The genome is the whole genetic material of an organism. It contains both the coding sequences, i.e. those that encode proteins, and the non-coding sequences. In most organisms, the genome is the DNA in the cells. However, in some viruses called retroviruses (eg HIV), the genetic material is RNA.
The answer is dusk and dawn.
Crepuscular animals are active during twilight (latin crepusculum). Twilight is a period after dawn and before dusk, so crepuscular animals want to avoid dusk and dawn. Animals' activity in different periods during the day depends on temperature or other biotic factors. It also depends on predators' activities or local competition.
Answer:
Assuming the dominant allele is represented as A, and the genotype as AA and the recessive as a, and genotype as aa; then the F1 will produce the offispring. Aa, Aa, Aa,Aa in ratio: 1:1:1:1:1
This shows the dominance of allele A.
However if two of the F1 generation are crossed then:
The F2 is AA,Aa,Aa,aa the phenotypic ratio is
3 ; 1
W<u>hile the Genotypic ratio is ratio;</u>
<u> 1AA : 2Aa Aa; 1aa(1 ;2;1)</u>
Explanation:
