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WARRIOR [948]
3 years ago
12

What is the solution to the equation (-14)+x-14

Mathematics
1 answer:
Fittoniya [83]3 years ago
3 0
I believe it would be A
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Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq
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Answer:

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Step-by-step explanation:

Let

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y----> the width of the rectangle

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x=y+5 ----> equation A

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substitute the equation A in equation B

120=(y+5)y+2(y+5)^{2}+2y^{2}

120=(y+5)y+2(y+5)^{2}+2y^{2}\\ 120=y^{2}+5y+2(y^{2}+10y+25)+2y^{2}\\ 120=y^{2}+5y+2y^{2}+20y+50+2y^{2}\\120=5y^{2}+25y+50\\5y^{2}+25y-70=0

using a graphing calculator -----> solve the quadratic equation

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4 0
4 years ago
Read 2 more answers
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