We have that
3sin x+cos²<span>x=2
</span>3sin x+(1-sin²x)<span>=2
</span>-sin²x +3sin x=1
sin²x -3 sin x+1=0---------> up to here the procedure is correct
let
A=sin x
then
A²-3A+1=0
Group terms that contain the same variable, and move the
constant to the opposite side of the equation
(A²-3A)=-1
Complete the square. Remember to balance the equation
by adding the same constants to each side.
(A²-3A+2.25)=-1+2.25
Rewrite as perfect squares
(A-1.5)²=1.25
(+/-)(A-1.5)=1.12
first solution
(A-1.5)=1.12--------> A=1.12+1.5-----> A=2.62-----> sin x=2.62
second solution
-(A-1.5)=1.12----> -A+1.5=1.12----> A=1.5-1.12----> A=0.38---> sin x=0.38
the answer is
the equation was factored incorrectly
Answer:
16.8
Step-by-step explanation:
just look at the length to the side of it (the "28") and look at the given answers. 4 seems way too small and because the line is shorter than 28 it cant be 43, so 16.8 is the most reasonable option.
You just have to multiply to remove the denominator.
x=1/16
Answer:
1. True
2. True
3. y = -1
4. False
Step-by-step explanation:
1 -------------------------
sin(-90) = -1
sin(270) = -1
True
2 --------------------------
y = cos(-90)
y = 0
True
3 -------------------------
y = tan(-45)
y = -1
-1
4 ---------------------------
tan(90) cannot be calculated
False
your answer is in the photo
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