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Zigmanuir [339]

2 years ago

9

Definition: A number greater than 0 is called ____.

2 answers:

lesya [120]2 years ago

6 0

They are called positive integers

natta225 [31]2 years ago

5 0

Answer:

a positive number as 0 is a neutral.

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What is the distance between (-5,8) and (-5.-8)

lisabon 2012 [21]

Answer: Use the formula y = mx + b in order to solve for b. Then, plug in known vaules.

y= -13x -57

Step-by-step explanation:

7 0

2 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Which of the following shows the number 7.12 x 10^-3 written in standard form? Answer choices : 0.00712 : 0.0712 : 0.712 : 7,120

svet-max [94.6K]

<span>written in standard form
</span><span>
7.12 x 10^-3 = 0.00712

hope it helps</span>

7 0

3 years ago

X + 4/5 =11 whats the value of x in simplest form

Tresset [83]

X= 11-4/5
x= 51/5 or 10.2

8 0

3 years ago

Andy used 1\6 of a can of paint to cover 1\2 of a wall. How much of the can of paint did Andy use to paint the whole wall? Expre

Y_Kistochka [10]

1/6 + 1/6 = 2/6 = 1/3

6 0

3 years ago

Read 2 more answers